Question

Consider a 2-way set associative cache with a total of 4096 lines. What is the minimum total number of bits required for the entire cache to implement an lru line replacement scheme?

Answer 1

The minimum total number of bits required for the entire cache to implement an lru line replacement scheme is 4096

Given:

cache is 2-way set associative implies in one set we will have 2 blocks (Hence k = 2).

To Find:

minimum total number of bits

Solution: Least Recently Used (LRU) algorithm is a page replacement technique used for memory management. According to this method, the page which is least recently used is replaced. Therefore, in memory, any page that has been unused for a longer period of time than the others is replaced.

Here Number of sets is = S = Number of blocks / 2 = 4096 / 2 = 2048. Hence Number of bits needed for LRU implementation is = 2048 * 2 * log2 2 = 4096

Hence, minimum total number of bits is 4096

Learn more about LRU here:

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