Moderno = mordern, if It does than yes!
Thank you for posting your question here. Below is the answer, I hope it helps.
int number = 0;
while (stdin.hasNextInt() && number >= 0){
number =stdin.nextInt();
if (number > 100)
System.out.print(number + " ");
<span>}</span>
Answer:
candyCost = int(input("How much is the candy?"))
Explanation:
candyCost = input("How much is the candy?") → By default, this how you get input and store the value. And it is stored as a string
candyCost = str(input("How much is the candy?")) → This also gives you a string to store
candyCost = float(input("How much is the candy?")) → This gives you a float number, decimal number, to store
candyCost = int(input("How much is the candy?")) → This gives you an integer number, a non-decimal
Answer:
You'd get a compiling error.
Explanation:
Since this code is presumably written in C++, it doesn't include an "int main()", and without it you'll have a compiling error when you create functions. Since the start of a C++ program is looking for "int main()" and one doesn't exist, the program cannot compile.
Since the only function here is the while statement, then that's what the compiler will scream at you for. If you put all of this code within an "int main()", you'll no longer have a compiling error, and you'll have "carbike" written to the console.
I hope this explanation helps! You're welcome!
