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4 years ago

PLS HELP ME IDK WHERE TO EVEN START...write the translation rule that maps P(-4,2) onto P'(-1,-1)

Mathematics

1 answer:

yawa3891 [41]4 years ago

7 0

<span>P(-4,2) onto P'(-1,-1)
rule
(x,y) ------------> (x + 3, y - 3)

hope it helps</span>

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Plz help me I have more questions coming up

kodGreya [7K]

<h3><u>Fraction to Decimal:</u></h3>

Divide the numerator (upper number) by the denominator (bottom number) on your calculator. Whatever number you get would be your decimal.

<h3><u>Decimal to Percent:</u></h3>

Take your decimal and use your calculator to multiply it by 100. Whatever number you get would be your percent. However, since it is a percent, you need to include the percentage unit.

<h3><u>Demonstration:</u></h3>

1/4 = 0.25

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4 years ago

A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

Artemon [7]

Answer:

a) The height decreases at a rate of $\frac{7}{12}$ ft/sec.

b) The area increases at a rate of $\frac{527}{24}$ ft^2/sec

c) The angle is increasing at a rate of $\frac{1}{12}$ rad/sec

Step-by-step explanation:

Attached you will find a sketch of the situation. The ladder forms a triangle of base b and height h with the house. The key to any type of problem is to identify the formula we want to differentiate, by having in mind the rules of differentiation.

a) Using pythagorean theorem, we have that $25^2 = h^2+b^2$ . From here, we have that

$h^2 = 25^2-b^2$

if we differentiate with respecto to t (t is time), by implicit differentiation we get

$2h \frac{dh}{dt} = -2b\frac{db}{dt}$

Then,

$\frac{dh}{dt} = -\frac{b}{h}\frac{db}{dt}$ .

We are told that the base is increasing at a rate of 2 ft/s (that is the value of db/dt). Using the pythagorean theorem, when b = 7, then h = 24. So,

$\frac{dh}{dt} = -\frac{2\cdot 7}{24}= \frac{-7}{12}$

b) The area of the triangle is given by

$A = \frac{1}{2}bh$

By differentiating with respect to t, using the product formula we get

$\frac{dA}{dt} = \frac{1}{2} (\frac{db}{dt}h+b\frac{dh}{dt})$

when b=7, we know that h=24 and dh/dt = -1/12. Then

$\frac{dA}{dt} = \frac{1}{2}(2\cdot 24- 7\frac{7}{12}) = \frac{527}{24}$

c) Based on the drawing, we have that

$\sin(\theta)= \frac{b}{25}$

If we differentiate with respect of t, and recalling that the derivative of sine is cosine, we get

$\cos(\theta)\frac{d\theta}{dt}=\frac{1}{25}\frac{db}{dt}$ or, by replacing the value of db/dt

$\frac{d\theta}{dt}=\frac{2}{25\cos(\theta)}$

when b = 7, we have that h = 24, then $\cos(\theta) = \frac{24}{25}$ , then

$\frac{d\theta}{dt} = \frac{2}{25\frac{24}{25}} = \frac{2}{24} = \frac{1}{12}$

7 0

3 years ago

Name two coordinates that are on the line: <img src="https://tex.z-dn.net/?f=y%20%3D%2012" id="TexFormula1" title="y = 12" alt="

Eva8 [605]

Answer:

(1,12) and (2,12).

(- 5,1) and (- 5, 2).

Step-by-step explanation:

y = 12 is a line that is parallel to the x-axis and at a constant distance of 12 units above the x-axis. Therefore, the points on the line will have any x-coordinate but have a constant y-coordinate i.e. 12.

Therefore, the two points on the line y = 12 can be (1,12) and (2,12).

x = - 5 is a line that is parallel to the y-axis and at a constant distance of 5 units left of the y-axis. Therefore, the points on the line will have any y-coordinate but have a constant x-coordinate i.e. - 5.

Therefore, the two points on the line x = - 5 can be (- 5,1) and (- 5, 2). (Answer)

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3 years ago

Hey come join! tzq axks npa<br> go ogle me et

tamaranim1 [39]

Answer:

sure :)

Step-by-step explanation:

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3 years ago

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