Question

Find the equation of the line that passes through the points (3,-2) and (6,-8)

Answer 1

Answer:

$2x + y = 4$

Step-by-step explanation:

The two-point form of the equation of a line is:

$y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)$

We have:

x1 = 3

y1 = -2

x2 = 6

y2 = -8

Plug in all the values where they belong in the equation above.

$y - (-2) = \dfrac{-8 - (-2)}{6 - 3}(x - 3)$

Simplify.

$y + 2 = \dfrac{-6}{3}(x - 3)$

$y + 2 = -2(x - 3)$

$y + 2 = -2x + 6$

$2x + y = 4$