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bearhunter [10]
3 years ago
11

What is the relationship between .04 and .004

Mathematics
2 answers:
IRINA_888 [86]3 years ago
4 0
They are both decimals.

But 0.04 > 0.004.
Alex73 [517]3 years ago
4 0
They both are decimals.
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If you run 100 meters in 10 seconds, what is your average speed
sertanlavr [38]

Answer:

Yeah it's 10

Step-by-step explanation:

100/10=10

6 0
3 years ago
Is there an ordered pair solutions to <br> -3x+3y=4 and <br> -x+y=3 ????
elixir [45]
Y=x+3
-3x+3(x+3)=4
-3x+3x+9=4
9=4
Since this statement is false, there are no ordered pair solutions to this problem.
8 0
3 years ago
Your next math test is worth 111 points and contains 32 problems. Each problem is worth either 4 points or 3 points. How many 3
Dafna11 [192]
We call x the 4 points-worth problems and y the 3 points-worth problems

You know that x+y = 32

4x+3y = 111

You know that the difference from the x and y is 32 so write:

x = 32-y

Substitute at x the value of 32-y

4(32-y)+3y = 111

128-4y +3y = 111

-4y+3y = 111-128

-y = -17

y = 17
3 0
3 years ago
Read 2 more answers
Write the contrapositive of the conditional statement. Determine whether the contrapositive is true or false. If it is false, fi
zubka84 [21]

Answer: A converse statement is formed by exchanging the hypothesis and conclusion of the conditional.

Step-by-step explanation:

8 0
3 years ago
It is possible to get 2 solutions when the system of equations is: (check all that apply)
SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as x^2+ y^2 = 1 ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

x^2 + x^2 = 1\\2x^2 = 1\\

x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }  so Y = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }

so the two solution are ( (\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} })

A system of the equation of a parabola and a linear equation

Let equation of Parabola be y^2 = x

and linear equation y = x

substitute

x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0
3 years ago
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