If the perimeter of equilateral triangle is 77 and the equation showing the perimeter is 6.5X-1 then the value of X is equal to 12.
Given that the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1.
We are required to find the value of X which is used in the expression.
Expression is combination of numbers, fraction, coefficients, indeterminants, determinants, which are mostly not found in equal to form.
Perimeter which is given is 77 and 6.5X-1.
6.5X-1=77
6.5X=77+1
6.5X=78
X=78/6.5
X=12
Hence if the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1 then the value of X is equal to 12.
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Answer: x=7
first, collect like terms:
5x-13=22
next move the constant to the right-hand side and change its sign:
5x=22+13
then add:
5x=35
lastly divide both sides of the equation by 5:
and you get.... x=7
hope this helps!! :))
Answer:
$7.81
Step-by-step explanation:
89¢ + 95¢ + $1.79 + $1.29 + $2.89
So numerically to add it the equation is...
0.89 + 0.95 + 1.79 + 2.89 + 1.29 = $7.81
In scientfic notation, it would be:
5.4 * 10^6
