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r-ruslan [8.4K]
1 year ago
7

How do I find the value of x that make lines u and v parallel

Mathematics
1 answer:
Sonbull [250]1 year ago
3 0
<h3>Answer:  x = 10</h3>

=======================================================

Explanation:

The square marker in the top left corner tells us we have a 90 degree angle. The 8x+10 must also be 90 degrees for lines u and v to be parallel. Refer to the alternate exterior angle theorem. Ignore the diagonal lines. Your teacher likely put them there as a distraction.

8x+10 = 90

8x = 90-10

8x = 80

x = 80/8

x = 10

You might be interested in
A graduate school entrance exam has scores that are normally distributed with a mean of 560 and a standard deviation of 90. What
9966 [12]

26.8% of examinees will score between 600 and 700.

This question is based on z score concept.

A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values. Z-score is measured in terms of standard deviations from the mean. If a Z-score is 0, it indicates that the data point's score is identical to the mean score.

z={x-\mu  \over \sigma }

where:

μ is the mean

σ is the standard deviation of the population

Given:

μ = 560

σ = 90

For

600≤ X≤700

for x = 700

Z score =x - μ/σ

=(700 - 560)/90

      = 1.55556

P-value from Z-Table:

P(560<x<700) = P(x<700) - 0.5 = 0.44009

for x = 600

Z score =x - μ/σ

=(600 - 560)/90

      = 0.44444

P-value from Z-Table:

P(560<x<600) = P(x<600) - 0.5 = 0.17164

∴ P(600<x<700) = P(560<x<700) - P(560<x<600)

                           = 0.44009 - 0.17164

                          =0.26845

∴26.8% percentage of examinees will score between 600 and 700.

Learn more about Z score here :

brainly.com/question/15016913

#SPJ4

4 0
1 year ago
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
Eight hundred forty nine divided by four
storchak [24]

Answer: 223.5

Step-by-step explanation:

3 0
3 years ago
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Find the area of a regular septagon (7 sided regular polygon) with side length 10.
allochka39001 [22]
A≈363.39
Your area is ^^
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Help please Im bout to fail.....
max2010maxim [7]

Answer:

it's the second to last one on the right side

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3 years ago
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