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hammer [34]
3 years ago
5

Yon buys tickets to a concert for himself and a friend. There is a tax of 6% on the price of the tickets and an additional booki

ng fee of $20 for the transaction. Write an algebraic expression to represent the price pre person. Simplify the expression if possible.
Mathematics
1 answer:
user100 [1]3 years ago
7 0
Well, I assume that both tickets cost the same: let's call it x.

So the tickets cost 106%x (the cost of the ticket plus tax).
The total prize of the tickets will be: 2*106% x+20.

But let's assume that you share it half-half: then each of you pays half of this:

\frac{2*1.06x+20}{2} = 1.06x+10


So, this is how much each of you pays: 1.06x+10
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How do you simplify this
Dafna11 [192]

Top:

x / (x + 1) - 1 / x

= [x^2 - (x +1)] / x(x+1)

= (x^2 - x - 1 ) / x (x+1)

Bottom:

x / (x + 1) + 1 / x

= [x^2 + (x +1)] / x(x+1)

= (x^2 + x + 1 ) / x (x+1)

Now you have:

(x^2 - x - 1 ) / x (x+1)

----------------------------

(x^2 + x + 1 ) / x (x+1)

= (x^2 - x - 1 ) / x (x+1) * x (x+1) / (x^2 + x + 1 )

= (x^2 - x - 1 ) /(x^2 + x + 1 )

Answer:

x^2 - x - 1

---------------------

x^2 + x + 1

7 0
3 years ago
Please help answer this question for me.
Lilit [14]

Answer:

Yes

Step-by-step explanation:

4 0
3 years ago
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

7 0
1 year ago
A sequence has the formula f(1)=4, f(4)= f(1) + f(n-1) for n>1.
Olegator [25]
Im so not good with these problems if you need help go to ask.com

5 0
2 years ago
Explain what needs to be fixed.<br> 2n + 10 = -2<br> 2n = 12 Step one<br> n = 6 Step two
Brilliant_brown [7]

Answer:

step one needs to be fixed... you are supposed to subtract 10 from both sides of the equation.

Step-by-step explanation:

STEP 1: Move all terms not containing n to the right side of the equation.

2n=-12

STEP 2: Divide each term by 2 and simplify.

n=-6

8 0
2 years ago
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