(2x+5)(x-4)=0 in standard form and value of a,b, and c
2 answers:
Answer:
a = 2 ; b = -3 ; c = -20
Step-by- step explanation:
Use FOIL method.
(2x + 5)(x - 4) = 0
2x*x+ 2x*(-4 )+ 5*x + 5* (-4) = 0
2x² - 8x + 5x - 20 =0
Combine like terms,
2x² - 3x - 20 = 0
Standard form: ax² + bx + x = 0
a = 2
b = -3
c = -20
hi
A = (2x+5)(x-4)=0
A = 2x²-8x +5x-20
A = 2x² -3x -20
as a quadratic equation is : ax² +bx +c
then a = 2 ; b = -3 and c = -20
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