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Colt1911 [192]
3 years ago
8

Which expression is not equivalent to the other expressions?

Mathematics
2 answers:
Ket [755]3 years ago
4 0
That would be D

the first 3 = -12x + 24

bur D  = -12x - 24
lina2011 [118]3 years ago
3 0

Answer:

That would be D

the first 3 = -12x + 24

bur D  = -12x - 24

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Can someone plz help me
Nata [24]

Answer:

A = 65, B = 75

Step-by-step explanation:

x + x + 10 + 40 = 180

2x + 50 = 180

2x= 130

x = 65

3 0
3 years ago
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. State the GCF of the terms in the expression 24xy" - 144x+y?. Then factor out the GCE.
Tamiku [17]
B on edge just got it
4 0
3 years ago
Alejandra can husk 8 ears of corn in 24 minutes. At this rate, how many ears of corn can she husk in 33 minutes?
8_murik_8 [283]
I'm afraid you're wrong. We may divide 24 by 8 to find out how long does it take for Alejandra to husk 1 ear of corn and then just divide 33 by the result:

24 ÷ 8 = 3

So Alejandra husks 1 ear of corn in 3 minutes.

33 ÷ 3 = 11

Answer: In 33 minutes Alejandra can husk <u>11 ears of corn</u>.
5 0
3 years ago
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Given the points below, are the two lines parallel, perpendicular, or neither?
Karo-lina-s [1.5K]

Answer:

none of them are perpendicular or parallel

5 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
Read 2 more answers
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