We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67
Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201
Now A-B can be written as:
A-B: 57c = 399
So c = 7
Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12
So s = 4
We have the price of a senior ticket is $4 and the price of a child ticket is $7
Answer:
A
Step-by-step explanation:
4x + 5 = 30 ( subtract 5 from both sides )
4x = 25 ( divide both sides by 4 )
x = 
Answer:
Step-by-step explanation:
(X²+2x+5)(2x)
= 2x(x²) +2x(2x) + 2x(5)
= 2x³ + 4x² + 10x
