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oksano4ka [1.4K]
2 years ago
8

Please help this is so hard for no reason

Mathematics
1 answer:
Anna007 [38]2 years ago
6 0

1. She is incorrect because in step 3, she did not make sure both sides of the equation have the same base.

2. Correct

3. Correct

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The _____ justifies the conclusion that ∆ABD ≅ ∆AEC.
elena55 [62]
It is the AAS Postulate.

Explanation: You’re given two right angles (because perpendicular sides make right angles).

This also means that the angle next to them are also right angles, because they are linear pairs (180-90=90)

The right angles are:
This is your first A.

Both triangles also share a similar angle:
This is your second A.

You’re given side BD is congruent to EC.

This is your S.

It’s AAS and not ASA because the order refers to how they are connected: they are congruent in the order that the first set of congruent angles connect to the next, then to the congruent side.
3 0
3 years ago
What is the slope of the line described by the equation below?
butalik [34]
Y = -6x + 3
In y = mx + b form, the slope will be in ur m position...

y = mx + b
y = -6x + 3

so ur slope (the number in the m position) is -6
4 0
3 years ago
If a chicken has 4kg of corn, how many days will it last it if it eats 1/8 of a kg of corn a day.
Gala2k [10]
It would take 32 days
7 0
3 years ago
Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
vladimir2022 [97]
What we know:
line P endpoints (4,1) and (2,-5) (made up a line name for the this line)
perpendicular lines' slope are opposite in sign and reciprocals of each other
slope=m=(y2-y1)/(x2-x1)
slope intercept for is y=mx+b

What we need to find: 
line Q (made this name up for this line) , a perpendicular bisector of the line p with given endpoints of  (4,1) and (2,-5)

find slope of line P using (4,1) and (2,-5) 
m=(-5-1)/(2-4)=-6/-2=3

Line P has a slope of 3 that means Line Q has a slope of -1/3.

Now, since we are looking for a perpendicular bisector, I need to find the midpoint of line P to use to create line Q. I will use the midpoint formula using line P's endpoints (4,1) and (2,-5).

midpoint formula: [(x1+x2)/2, (y1+y2)/2)]
midpoint=[(4+2)/2, (1+-5)/2]
              =[6/2, -4/2]
              =(3, -2)

y=mx=b       when m=-1/3 slope of line Q and using point (3,-2) the midpoint                                 of line P where line Q will be a perpendicular bisector

(-2)=-1/3(3)+b               substitution
-2=-1+b                           simplified
-2+1=-1+1+b                 additive inverse
-1=b

Finally, we will use m=-1/3 slope of line Q and y-intercept=b=-1 of line Q
y=-1/3x-1



4 0
3 years ago
Read 2 more answers
Oop help plzzzzz this is ALOTE OF MY GRADE! HELP RIGHT AWAY ILL GIVE 20 POINTS PLZ HELP
sertanlavr [38]

Answer:

its B ITHINK

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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