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DochEvi [55]
3 years ago
8

Not asking a question, but i just wanted to thank every single one of you answering questions, you've helped me so much.

Mathematics
2 answers:
atroni [7]3 years ago
5 0

Answer:

I know that many people have helped u and I appreciate that you are thanking them.

Step-by-step explanation: Happy early Valentine’s Day!

Pachacha [2.7K]3 years ago
5 0

Answer:

yw

Step-by-step explanation:

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Is a click and drag and.
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Hi! i can’t see song central. but, song factory is more expensive than music mania because song factory is 1.75 a download and music mania is 1.50 a download
4 0
1 year ago
If Sally walked 1⁄2 mile in 1⁄6 hour, how fast, in miles per hour, was she walking?
amm1812
.5 miles in 1/6 hour

multiply both by 6

3 miles in 1 hour

3 miles per hour
5 0
3 years ago
Read 2 more answers
Hi i need help with this
pogonyaev

Answer:

15 in

Step-by-step explanation:

d^2 = w^2 + l^2

25^2 = 20^2 + l^2

l^2 = 225

l = 15

5 0
2 years ago
An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling
kondaur [170]
<h2>Hello! It will be a pleasure to help you! </h2><h2>So let's get started:</h2><h3 /><h2>PART 1. </h2><h3>An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling rate?</h3>

Sampling is simply a reduction of a continuous time signal to a discrete time signal. Here we know that an analogue sensor is sampled every 0.4ms to convert it into a digital representation. So sampling rate, also called the sampling frequency or f_{s}, is the average number of samples obtained in one second, that is, samples per second:

f_{s}=\frac{1}{T}

Since we know:

T=0.4ms

Then, the sampling rate is:

f_{s}=\frac{1}{0.4ms} \\ \\ f_{s}=2,500 \ samples \ per \ second \\ \\ Or: \\ \\ \boxed{f_{s}=2.5kS/s}

<h3 /><h2>PART 2. </h2><h3>According to the Sampling Theorem, for this sampling rate value, what will be the highest frequency in the digital representation, assuming the lowest frequency in the sensor signal is very close to zero.</h3><h3 />

Sampling Theorem (Nyquist Theorem) States:

<em>A </em><em>continuous time signal </em><em>can be completely represented in its samples and recovered back, if the sampling frequency </em>f_{s} <em>is greater than or equal to twice frequency component of the message signal.</em>

In other words:

f_{s}\geq 2f_{m}

So, the highest frequency in the digital representation will be:

f_{m}=\frac{2500}{2} \\ \\ \boxed{f_{m}=1.25kHz}

<h2>PART 3. </h2><h3>If each sample is quantised into 2048 levels, what will be the resulting bit-rate, giving your answer in scientific notation to 2 decimal places?</h3>

Everything is Ok up to this point! But let me explain something. We do all these things in order to get a faithful reproduction of the digital signal. So the Analog-to-Digital Conversion (ADC) allows us to do that.

In this final part, each sample is quantised to 2048 levels, so this number can be written as:

2048=2^{11}

That is, there are (2^{11}) \ levels, in other words, it takes:

11 \ bits \ per \ sample

Finally, the resulting bit-rate is:

11 \times 2500 \\ \\ =27500 \ bits \ per \ second

In scientific notation to two decimal places:

\boxed{2.75 \times 10^4 \ bits \ per \ second}

8 0
3 years ago
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