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DochEvi [55]
3 years ago
8

Not asking a question, but i just wanted to thank every single one of you answering questions, you've helped me so much.

Mathematics
2 answers:
atroni [7]3 years ago
5 0

Answer:

I know that many people have helped u and I appreciate that you are thanking them.

Step-by-step explanation: Happy early Valentine’s Day!

Pachacha [2.7K]3 years ago
5 0

Answer:

yw

Step-by-step explanation:

You might be interested in
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu
Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

Total                  2298                     170                  2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0
3 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

4 0
3 years ago
Will mark barinly______
Lady_Fox [76]

Answer:

x = 13

y = 15

Step-by-step explanation:

ST = DT ( Reason : from given )

5x = 65

x = 65 / 5

x = 13

TY = TU ( Reason : from given )

3y + 5 = 50

3y = 50 - 5

3y = 45

y = 45 / 3

y = 15

8 0
3 years ago
Pippi sold ten more cups of lemonade that cups of iced tea. She sold 120 cups in all. How many cups of lemonade did she sell?
Kamila [148]

Answer:

65  cups

Step-by-step explanation:

If she sold 10 more cups of lemonade than tea and sold 120 cups total.  I first would subtract 10 cups from 120 =110.  then I divide 110 /2 = 55 cups

The 55 cups makes it equal then I add the 10 cups back to the Lemonade to get 55+10 = 65

So your answer would be 65 cups of lemonade

7 0
3 years ago
Find the range of the data set 145, 612, 120, 349, 515, 212, 590.
storchak [24]

Answer:

The biggest - the smallest

612-120=492

6 0
2 years ago
Read 2 more answers
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