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Neporo4naja [7]
2 years ago
14

In the above figure, m AOC=26 and m BOD= (2x+39). If AOC and BOD are vertical angles whats the value if x?

Mathematics
1 answer:
Reika [66]2 years ago
4 0

If AOC and BOD are vertical angles, the value of x is x = -6.5

<h3>How to determine the value of x?</h3>

The angles are given as:

m AOC = 26

m BOD = (2x+39).

From the question, we have

AOC and BOD are vertical angles

Vertical angles are equal.

So, we have:

AOC = BOD

Substitute the known values in the above equation

2x + 39 = 26

Subtract 39 from both sides

2x = -13

Divide bot sides by 2

x = -6.5

Hence, if AOC and BOD are vertical angles, the value of x is x = -6.5

Read more about vertical angles at

brainly.com/question/14362353

#SPJ1

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Flura [38]

9 and 1/2 is the answer. We can find this by simply subtract 1 1/2 from 12.

7 0
3 years ago
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Donte is making a pizza. The round pizza pan has a 18 inch diameter. What is the area of the Pizza crust will need to fill up th
Fittoniya [83]
A = pi(r)^2
diameter is 18in, so radius is 9in
= pi(9)^2
A = 254.469 (round is needed)
8 0
3 years ago
In preperation for an easter egg hunt, 4 blue eggs are filled for every 7 green. How many green eggs will be filled if 100 blue
ivann1987 [24]

Answer:

1. Typed question: 175 green eggs

2. Attached: 22 tables

Step-by-step explanation:

For the question you typed down, it is a ratio and proportion problem. You need to solve for the ratio proportional to the first ratio given.

4 blue eggs are filled for every 7 green. This means that the ratio between blue eggs and green eggs is 4:7.

Now yo need to figure out a ratio proportional to 4:7 if 100 blue eggs were filled. Below is how this is set up:

\dfrac{4\;blue\;eggs}{7\;green\;eggs} = \dfrac{100\;blue\;eggs}{x\;green\;eggs}

Now let's solve for x:

\dfrac{4\;blue\;eggs}{7\;green\;eggs} = \dfrac{100\;blue\;eggs}{x\;green\;eggs}\\\\or\\\\\dfrac{4}{7}=\dfrac{100}{x}\\\\Cross-multiply\\\\4x = (7)(100)\\\\4x = 700\\\\Divide\;both\;sides\;by\;4\\\\\dfrac{4x}{4}=\dfrac{700}{4}\\\\x=175

For your attached problem:

You have a total of 175 people, you need to figure out how many round tables you need if here are 8 chairs for each table You just need to divide the number of people by the number of chairs per table.

175 ÷ 8 = 21.9 tables

Now since you cannot have half a table, you round up to the nearest whole number. (we round up because you need to make sure that all of them are seated)

21.9 ≅ 22 tables.

8 0
4 years ago
What is
Sergeeva-Olga [200]

Answer:

Standard form of the equation is:

∴ 3x+y=23

Step-by-step explanation:

Given equation:

y-2=-3(x-7)

To convert the given equation to standard form of equation:

A(x)+B(y)=c

Using distribution.

y-2=(-3x)+(-3\times-7)

y-2=-3x+21

Adding 2 both sides.

y-2+2=-3x+21+2

y=-3x+23

Adding 3x to both sides.

3x+y=3x-3x+23

∴ 3x+y=23

6 0
3 years ago
This 1 seems really complicated
Fofino [41]
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
________________________________________________________
Given: 
________________________________________________________
 y = - 4x + 16 ; 

 4y − x + 4 = 0 ;
________________________________________________________
"Solve the system using substitution" .
________________________________________________________
First, let us simplify the second equation given, to get rid of the "0" ; 

→  4y − x + 4 = 0 ; 

Subtract "4" from each side of the equation ; 

→  4y − x + 4 − 4 = 0 − 4 ;

→  4y − x = -4 ;
________________________________________________________
So, we can now rewrite the two (2) equations in the given system:
________________________________________________________
   
y = - 4x + 16 ;   ===> Refer to this as "Equation 1" ; 

4y − x =  -4 ;     ===> Refer to this as "Equation 2" ; 
________________________________________________________
Solve for "x" and "y" ;  using "substitution" :
________________________________________________________
We are given, as "Equation 1" ;

→  " y = - 4x + 16 " ;
_______________________________________________________
→  Plug in this value for [all of] the value[s] for "y" into {"Equation 2"} ;

       to solve for "x" ;   as follows:
_______________________________________________________
Note:  "Equation 2" :

     →  " 4y − x =  - 4 " ; 
_________________________________________________
Substitute the value for "y" {i.e., the value provided for "y";  in "Equation 1}" ;
for into the this [rewritten version of] "Equation 2" ;
→ and "rewrite the equation" ;

→   as follows:  
_________________________________________________

→   " 4 (-4x + 16) − x = -4 " ;
_________________________________________________
Note the "distributive property" of multiplication :
_________________________________________________

   a(b + c)  = ab + ac ;   AND: 

   a(b − c) = ab <span>− ac .
_________________________________________________
As such:

We have:  
</span>
→   " 4 (-4x + 16) − x = - 4 " ;
_________________________________________________
AND:

→    "4 (-4x + 16) "  =  (4* -4x) + (4 *16)  =  " -16x + 64 " ;
_________________________________________________
Now, we can write the entire equation:

→  " -16x + 64 − x = - 4 " ; 

Note:  " - 16x − x =  -16x − 1x = -17x " ; 

→  " -17x + 64 = - 4 " ;   Solve for "x" ; 

Subtract "64" from EACH SIDE of the equation:

→  " -17x + 64 − 64 = - 4 − 64 " ;   

to get:  

→  " -17x = -68 " ;

Divide EACH side of the equation by "-17" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  -17x / -17 = -68/ -17 ; 

to get:  

→  x = 4  ;
______________________________________
Now, Plug this value for "x" ; into "{Equation 1"} ; 

which is:  " y = -4x + 16" ; to solve for "y".
______________________________________

→  y = -4(4) + 16 ; 

        = -16 + 16 ; 

→ y = 0 .
_________________________________________________________
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
_________________________________________________________
Now, let us check our answers—as directed in this very question itself ; 
_________________________________________________________
→  Given the TWO (2) originally given equations in the system of equation; as they were originally rewitten; 

→  Let us check;  

→  For EACH of these 2 (TWO) equations;  do these two equations hold true {i.e. do EACH SIDE of these equations have equal values on each side} ; when we "plug in" our obtained values of "4" (for "x") ; and "0" for "y" ??? ; 

→ Consider the first equation given in our problem, as originally written in the system of equations:

→  " y = - 4x + 16 " ;    

→ Substitute:  "4" for "x" and "0" for "y" ;  When done, are both sides equal?

→  "0 = ?  -4(4) + 16 " ?? ;   →  "0 = ? -16 + 16 ?? " ;  →  Yes!  ;

 {Actually, that is how we obtained our value for "y" initially.}.

→ Now, let us check the other equation given—as originally written in this very question:

→  " 4y − x + 4 = ?? 0 ??? " ;

→ Let us "plug in" our obtained values into the equation;

 {that is:  "4" for the "x-value" ; & "0" for the "y-value" ;  

→  to see if the "other side of the equation" {i.e., the "right-hand side"} holds true {i.e., in the case of this very equation—is equal to "0".}.

→    " 4(0)  −  4 + 4 = ? 0 ?? " ;

      →  " 0  −  4  + 4 = ? 0 ?? " ;

      →  " - 4  + 4 = ? 0 ?? " ;  Yes!
_____________________________________________________
→  As such, from "checking [our] answer (obtained values)" , we can be reasonably certain that our answer [obtained values] :
_____________________________________________________
→   "x = 4" and "y = 0" ;  or; write as:  [0, 4]  ;  are correct.
_____________________________________________________
Hope this lenghty explanation is of help!  Best wishes!
_____________________________________________________
7 0
3 years ago
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