Answer:
Since the equation is a quadractic, the graph would be a parabola.
With a being -1, the parabola will represent a reflection of the y values. In other words, the parabola will be upside down and the vertex will be a maximum value. Ultimately, the <em>a </em>in the function doesn't determine the location of the vertex.
Since the k value is negative, that means the equation begins <em>y - (-k)</em>. The K value being negative restricts the transformation of the parabola to being down <em>k</em> number of units. The location of moving the parabola down places the vertex in the third or fourth quadrant.
The <em>h</em> value being positive means that the parabola is shifted to the right <em>h</em> number of units. For example, if the parabola <em>f(x) = x² </em>has a vertex at (0,0), the parabola <em>f(x) = (x-2)²</em> must have a vertex at (2,0) because 2 - 2 = 0. Shifting right places the vertex of the parabola in the first or fourth quadrant.
Therefore the k value and h value restrictions must overlap in the fourth quadrant.
Step-by-step explanation:
<span>Approximately 11 days old</span>
Answer:
84°
Step-by-step explanation:
1. <u>point of intersection of 2y=x-13 and 3y+x+12=0</u>
x = 2y + 13 ==> 3y + (2y+13) + 12 = 0 ==> 5y + 25 = 0 ==> y = -5
x = 2*(-5) +13 = 3
point of intersection: (3 , -5) L1: pass (3 , -5) and (-4 , -7)
slope of L1 = (-7 - -5)/(-4-3) = -2 / -7 = 2/7
L2 pass (3 , -5) perpendicular to 2x-5y=4
2x-5y=4 ==> y = 2/5 x - 4 slope = 2/5
so slope of L2 = -5/2
angle Θ between two slopes: tan Θ = | (m2-m1) / (1 + m1*m2)|
==> = | (-5/2 - 2/7) / (1 + -5/2*2/7) | = |(-39/14) / (4/14) | = |- 39/4| = 39/4 = 9.75
Θ = 84°
There is 6 regular packs and 6 value packs so add those (6+6=12). Divide 12 by 2 (because there's 2 socks in a pair) and get 6. Then divide 402 by 6 and get 67 pairs. Do the same for the second location.
First we need to turn 1 5/7 into an improper fraction 7x1+5 = 12/7
12 / 7 x 5 / 6 = 60/42 ....reduced.....10/7
10/7 as a mixed number is 1 3/7
