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Svetradugi [14.3K]
3 years ago
13

What is the base area of the cone?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

Step-by-step explanation:

In order to find the area of the circle base, we need the radius, and we don't have it. We'll use the volume to find the radius, as follows:

V=\frac{1}{3}\pi r^2h and fill in the givens:

75=\frac{1}{3}\pi r^2(5) and solve that for r;

r=\sqrt{\frac{3(75)}{5\pi} } so

r = 3.784698783 and plug that in for the radius to find the area of the circle base:

A=\pi r^2 so

A=\pi (3.784698783)^2 gives you that

A = 45 meters squared, exactly. No decimal.

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WILL GIVE BRAINLIEST find the value of r (-4,8), (r,12), m=4/3 (show your work pls)
OLEGan [10]

Answer:

r = 13

Step-by-step explanation:

The first step is to find b from y=mx=b using m=4/3 and (-4,8)

8=\frac{4}{3}(-4)+b

After solving the equation, b will equal -16/3 making the final equation be

y=\frac{4}{3} x-\frac{16}{3}

Using the equation, you can solve for r.

12=\frac{4}{3} x-\frac{16}{3}

This will bring the answer being r = 13

7 0
3 years ago
Factor the expression 20k + 50
Yuliya22 [10]
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
4 0
3 years ago
What are the roots of the polynomial equation? x² + 7x + 12 = 0 Enter your answers in the boxes. x1= x2=
oksian1 [2.3K]
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3 0
3 years ago
Read 2 more answers
A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
Nesterboy [21]

Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,  

n = Number of times interest is compounded per year,

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

1000=P(1+\frac{0.06}{0.5})^{0.5*6}

1000=P(1+0.12)^{3}

1000=P(1.12)^{3}

1000=P*1.404928

\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}

P=711.7802478

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Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

7 0
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What gradient is shown in the graph
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Answer:

-2/1 or -2

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in an equation this would be y=-2x-3

5 0
2 years ago
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