Part a)
for extraneous solution
<span>
1 ⋅ sqrt(x+2) + 3 = 0</span>
for non extraneous solution
1⋅ sqrt(x+2) + 3 = 6
part b) solve each equation
1⋅sqrt(x+2)+3=0
x+sqrt(x+2)=−3
square both sides
(sqrt(<span>x+2)</span>)^ 2 = (−3)^2
x+2=9
x=9−2
x=7
do you see why its extraneous
Answer:
x≥ 0
Step-by-step explanation:
7x+6 ≥ -(x-6)
Distribute the minus sign
7x+6 ≥ -x+6
Add x to each side
7x+x+6 ≥ -x+x+6
8x+6 ≥ 6
Subtract 6 from each side
8x+6-6 ≥ 6
8x≥ 0
Divide by 8
8x/8≥ 0/8
x≥ 0
Answer:
The functions that represent this situation are A and C.
Step-by-step explanation:
A geometric sequence goes from one term to the next by always multiplying or dividing by the same value.
In geometric sequences, the ratio between consecutive terms is always the same. We call that ratio the common ratio.
This is the explicit formula for the geometric sequence whose first term is k and common ratio is r
