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storchak [24]
3 years ago
8

Jenifer needs to purchase a computer for her company price of the computer is c

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

If you provide more information then I could try to help :)

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jenell wants to invest $5800 in a savings account that pays 6.6% simple interest. how long will it take for this investment to d
solong [7]
30.35 years so 31 years
5 0
2 years ago
An engineer estimated the weight of a steel beam to be 600 pounds. The actual weight of the beam was 639 pounds. Find the absolu
mario62 [17]

Answer:

Absolute error = 39

Percent Error = 6.10%

Step-by-step explanation:

Actual value = 639 pounds

Observed Value = 600 pounds

The formula to find absolute error is:

Absolute Error = Actual value - Observed Value

                        = 639 - 600

                        = 39

The formula to find Percent error is:

Percent Error = (Actual value - Observed Value / Actual value)*100

                       = (639 - 600/639)*100

                       = 6.10%

                 

7 0
2 years ago
Read 2 more answers
Select the answer choice that is equivalent to the expression given belon.
uranmaximum [27]

Answer:

23x - 10

Step-by-step explanation:

To the find the equivalent of 9(2x - 3) + 5x + 17, evaluate the expression. Start by opening the bracket.

9*2x - 9*3 + 5x + 17

18x - 27 + 5x + 17

Pair like terms

18x + 5x - 27 + 17

23x - 10

The equivalent of 9(2x - 3) + 5x + 17 is 23x - 10

6 0
3 years ago
I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!
evablogger [386]

Answer:

The answer is 6

Step-by-step explanation:

The answer is 6

5 0
3 years ago
For each of the following scenarios state whether H0 should be rejected or not. State any assumptions that you make beyond the i
scoundrel [369]

Answer:

a)H_0 :\mu = 4\\ H_1 : \mu \neq 4 , n = 15 , X=3.4 , S=1.5 , α = .05

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{3.4-4}{\frac{1.5}{\sqrt{15}}}

t =-1.549

p- value = 0.607(using calculator)

α = .05

p- value > α

So, we failed to reject null hypothesis

b)H_0 :\mu = 21\\ H_1 : \mu < 21 , n =75 , X=20.12 , S=2.1 , α = .10

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{20.12-21}{\frac{2.1}{\sqrt{75}}}

t =-3.6290

p- value = 0.000412(using calculator)

α = .1

p- value< α

So, we reject null hypothesis

(c) H_0 :\mu = 10\\ H_1 : \mu \neq 10, n = 36, p-value = 0.061.

Assume α = .05

p-value = 0.061.

p- value > α

So, we failed to reject null hypothesis

7 0
2 years ago
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