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3 years ago

How can I solve this system of equation with substitution u+6y=32 and u+3y=17

Mathematics

2 answers:

Ne4ueva [31]3 years ago

6 0

U+6y=32 U+3y=17

Solve U+6y=32 for u

Add -6y to both sides

U+6y-6y=32-6y U= -6y+32

Substitute -6y+32 for U in U+3y=17 U+3y=17 -6y+32+3y=17

Simplify both sides of the equation -3y+32=17

Add -32 to both sides -3y+32-32=17-32 -3y=-15

Divide both sides by -3 -3y/-3 = -15/-3 Y=5

Substitute 5 for y in U=-6y+32 U= -6y+32

U= (-6)(5)+32 u= -30 +32 U= 2

Answer : U= 2 and Y=5

I hope that's help and have a great night !

gayaneshka [121]3 years ago

5 0

U= 32 - 6y
u = 17 - 3y

Step 1
32 - 6y = 17 - 3y

Step 2
-6y + 3y = 17 - 32

Step 3
-3y = - 15

Step 4
3y = 15

Step 5
y = 15/3

Step 6
y = 5

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If the weight (in grams) of cereal in a box of Lucky Charms is N(489,6), what is the probability that the box will contain less

Wittaler [7]

Answer:

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N(489,6)

This means that $\mu = 489, \sigma = 6$

What is the probability that the box will contain less than the advertised weight of 466 g?

This is the p-value of Z when X = 466. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{466 - 489}{6}$

$Z = -3.83$

$Z = -3.83$ has a p-value of 0.000064

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

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2 years ago

Use any order, any grouping to write an equivalent expression: 3(2x) + 4y(5) + (4 x 2 x z)

enyata [817]

Answer:

We conclude that the equivalent expression is:

$3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z$

Step-by-step explanation:

Given the expression

$3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)$

Remove parentheses: (a) = a

$=3\times \:2x+4\times \:5y+4\times \:2z$

Multiply the numbers: 3 × 2 = 6

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Multiply the numbers: 4 × 5 = 20

$=6x+20y+4\times \:2z$

Multiply the numbers: 4 × 2 = 8

$=6x+20y+8z$

Thus, we conclude that the equivalent expression is:

$3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z$

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Step-by-step explanation:

thats your answer XD

3 0

3 years ago