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faltersainse [42]
3 years ago
6

If f(x)=3x-1 and g(x)=x+2, find (f+g)(x)

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

4x +1 is your answer.

Step-by-step explanation:

What you do is you add f(x) and g(x) together.

<em>3x - 1 + (x + 2)</em>

4x +1 is your answer.

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What is the answer<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B6%7D%20%20%2B%20%20%5Cfrac%7B12%7D%7B12%7D%20" id="T
bija089 [108]

<u>I think answer is 2.5</u>

HOPE THIS HELPS YOU

5 0
3 years ago
Write 6 × 10 -7 in decimal notation.<br><br> 0.0000006<br> 0.00006<br> 600,000<br> 6,000,000
Lina20 [59]
I’m pretty sure the answer is B
3 0
3 years ago
Help pls thank you so much
azamat

Answer:

$179.20

Step-by-step explanation:

use the formula retail price = original price + markup

Step One: Convert 28% to a decimal

--> 0.28

Step two: Plug all the numbers into the equation

--> $140 + $140 x 0.28 = $179.20

Give brainliest if this was helpful! Thanks! Have an amazing day!

5 0
3 years ago
3x+5+4x+6<br>simplify this
zloy xaker [14]
Just simply collect like terms.

3x+4x+5+6
7x+11
7 0
4 years ago
Read 2 more answers
Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and
SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

f(x)=\left\{\begin{array}{l}x+9,\ \ x

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For x

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18

2. For x\ge 9:

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18

So, limit exists and is equal to 18.

8 0
3 years ago
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