Explanation:
You want to find the angle at the point of intersection when two secants intersect each other outside a circle.
<h3>Secant relation</h3>The attachment shows secants AD and AE that meet at point A outside the circle. The secants intersect the circle at B and C, respectively, intercepting arcs BC and DE.
The measure of the angle at A, the point where the secants intersect each other, is half the difference of the measures of arc DE and arc BC:
∠A = (arc DE -arc BC)/2
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<em>Additional comment</em>
When points B and D coincide, the secant becomes a tangent. The same angle relation still holds.
When the two secants become <em>two tangents</em>, the measure of angle A can still be found as the difference of the intercepted arcs. In that case, since the arcs together form the whole circle, <em>angle A is the supplement of arc BC</em>.
For this case we have that, by definition, the equation of a line in the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cutting point with the y axis
We have, according to the statement data that:
So, the equation is of the form:
We also have that the line intersects the "x" axis at -3, that is, the line passes through the point
We substitute to find "b":
Finally, the equation is of the form:
Answer:
