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2 years ago

Can someone please simplify ln e^4/8 showing me how to do it

Mathematics

1 answer:

Otrada [13]2 years ago

6 0

Answer:

e ^1/2

Step-by-step explanation:

All you do is take the fraction (4/8) and just simplify that part

4 divided by 2 = 2

8 divided by 2 =4

I got 2/4 but I can simplify more

2 divided by 2= 1

4 divided by 2 = 2

Now I got 1/2

And I would just leave e alone so my answer is e ^1/2

Do you kinda get what im saying?

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Which statement describes the end behavior of this function? f(x)=log(x-2)

andrezito [222]

Answer:

Step-by-step explanation:

this because it is what it is and therefore henceforth ergo this is correct so according to ir doubt i feel like u are really smart

7 0

2 years ago

In the Central Grand Prix, out of 30 cars that started the race, 12 of them finished. What percent of the cars finished the race

zvonat [6]

Answer:

40% finished, which means that 60% did not.

Step-by-step explanation:

a = p*w

12 = p*30

12/30=p

.40 = p

40%

6 0

3 years ago

Which expression best estimates 6 and three-fourths divided by 1 and two-thirds?

bixtya [17]

Answer: The expression is 7/2.

3 0

2 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago

Find the indicated function values

kupik [55]

Answer:

f(-4) = 6

f(0) = -6

f(1) = -4

Step-by-step explanation:

6 0

2 years ago