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Ipatiy [6.2K]
1 year ago
12

Which amino acid might be expected to have the least effect on the function of an enzyme if it replaces a glu residue in the enz

yme?
Biology
1 answer:
My name is Ann [436]1 year ago
7 0

Aspartic acid (Asp) amino acid might be expected to have the least effect on the function of an enzyme if it replaces a glu residue in the enzyme.

Aspartic acid, like glutamic acid, is assessed as an acidic amino acid, but in a peptide that is relatively depending on the neighborhood surroundings,

Aspartic acid the ionic form is referred to as aspartate, is an α-amino acid this is used in the biosynthesis of proteins. like all different amino acids, it contains an amino organization and a carboxylic acid. Its α-amino organization is in the protonated –NH+.

Aspartic acid has an acidic side chain (CH2COOH) which reacts with other amino acids, enzymes and proteins within the frame. Beneath physiological conditions in proteins the aspect chain commonly happens because the negatively charged aspartate

Learn more about amino acid here:-brainly.com/question/2526971

#SPJ4

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sashaice [31]

Answer: The correct option is A (chromosome Number is reduced from diploid to haploid)

Explanation:

In sexual reproduction, offspring are produced by fusion of two different sex cells which usually come from two different parents. These sex cells are know as gametes.

Meiosis is a type of cell division that gives rise to gametes in which the chromosome number is halved. Thus, the gamete cell is said to contain a haploid number (n) of chromosomes.

A diploid cell has two sets of chromosomes: one from the male parent and the other from the female parent. When a diploid cell undergoes meiosis the following occurs:

--> the chromosomes replicate once and

--> the nucleus and cell duplicate ( divide equally) twice.

As a result, the diploid parent cell gives rise to four haploid gamete cells. Therefore the statement "chromosome Number is reduced from diploid to haploid ' is true concerning meiosis I.

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I think your on track with C.

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