Answer:
The difference is the organization of the fibers located in the extracellular matrix.
Explanation:
The connective tissue gives support and structure to other tissues and organs. Diverse cells, fibers and ground substance (matrix) are components of the connective tissue. The connective tissue is classified in: loose or dense. As their names imply, loose connective tissue has fewer cells and fibers per area whereas in the dense connective tissue the cells and fibers are tightly packed. The dense connective tissue is further divided into regular and irregular. The main difference is the arrangement of the fibers in these tissues. In the regular dense connective tissue, all the fibers are oriented in one direction. In contrast in the irregular dense connective tissue the fibers have multiple orientations
If a red blood cell is placed in a hypertonic solution, the cell would shrink.
Hypertonic solution means that the solution has a lower water potential than the other side (which is the cell's cytoplasm in this case), and by that, water molecules would have a tendency to flow from a region of higher water potential to a region of lower water potential. This movement of water molecules is called osmosis. But note that a semi-permeable membrane (a membrane which can decide what substances can go in and out, the cell membrane is an example) has to be present in osmosis, or else the movement may be regarded as diffusion.
As the water molecules flowed away from the red blood cell cytoplasm, the cell loss so much water that the membrane has nothing much to hold and thus the cell shrinks.
Spring often comes after winter
Answer:
You missed the specific heat on water, that is 1 calorie/gram °C. This answer is, 0.12°C
Explanation:
The stayment says, that all of the energy from the pancake is transferred into the water, so we have to think that 61 calories are burned in the calorimeter with water. Let's apply on the formula.
Heat added = specific heat x mass x (tfinal - tinitial)
61 cal = 500. g .1 cal/g °C . ΔT
61 cal / 500 g / 1 cal/g °C =ΔT
0.12 °C = ΔT
