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Maslowich
1 year ago
14

The United States earned 104 medals at the 2012 summer olympics. The number of silver medals earned was the same as the number o

f bronze medals. The number of gold medals was 17 more than the number of silver medals. How many of each kind of medal did the united states earn?
Mathematics
1 answer:
Lapatulllka [165]1 year ago
6 0

Answer-29 bronze, 46 gold,and 29 silver.

The first thing to do is take 104 and subtract the 17 medal difference between them all. This is 87. Next we divided 87 into three, which gives us 29. Now we have 29 medals for silver, bronze, and gold. However we must add 17 to the gold medals that we took away earlier. 29+17 is 46. To make sure this is correct we can add 29+29+46. This equals 104, which our original answer, so this was correct.

In 2012 the United States earned 29 bronze medals, 46 gold medals, and 29 silver medals.

HOPE THIS HELPS!! GOOD LUCK!!! <3

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8 + 5n - 6, use n = 6
emmainna [20.7K]
8+5n-6

8+5(6)-6

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38-6

32

32 is the answer.

I hope this helps!
~kaikers
4 0
3 years ago
Suppose that many large samples are taken from a population and that the
rewona [7]

Answer:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

\bar X = 0.22

And the standard error is given by:

SE = 0.029

We want to construct a 68% confidence interval so then the significance level would be :

\alpha=1-0.68 = 0.32 and \alpha/2 =0.16. The confidence interval is given by:

\bar X \pm z_{\alpha/2} SE

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

z_{\alpha/2}= 1

And replacing we got:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

5 0
3 years ago
(ASAP)Someone help me out please
ludmilkaskok [199]

Answer:

Y= 1/3x + 4

Step-by-step explanation:

4 is the y intercept and it goes across one and down 3 for the get the slope of  1/3.

8 0
3 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
NEED HELP ASAP PLEASE!!!!!
faust18 [17]

Answer:

  1. 한차례ㅎ츟ㅎ츟
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  3. <em><u>ㅎ요유ㅛㅇ</u></em>
  4. <em><u>ㅓ요둉ㅎ됴</u></em>
  5. <em><u>ㅎㅊ랻</u></em>
  6. <em><u>여곻</u></em>
  7. <em><u>여려ㅑㅗ고도오</u></em>
6 0
3 years ago
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