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2 years ago

The polynomial is missing the coefficient of the third and last terms.

1 answer:

8 0

In order to divide polynomials using synthetic division, you must be dividing by a linear expression and the leading coefficient (first number) must be a 1. For example, you can use synthetic division to divide by x + 3 or x – 6, but you cannot use synthetic division to divide by x2 + 2 or 3x2 – x + 7. If the leading coefficient is not a 1, then you must divide by the leading coefficient to turn the leading coefficient into a 1. For example, 3x – 1 would becomex minus 1/3 and 2x + 7 would becomex plus 7/2. If synthetic division will not work, then you must use long division.

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Find the next two terms in the sequence. 0, 1, 4, 9, . . . a. 13, 18 b. 13, 17 c. 16, 23 d. 16, 25

Roman55 [17]

Well, we knew that from 0 to 1 you add '1', from 1 to 4 you add '3', from 4 to 9 you add '5', from 9 to ? you add '7'!

So 9+7=16.

16 to ? you add 9! 16+9=25

The next 2 terms are 16 and 25.

7 0

2 years ago

The sum of three consecutive rven integers is 72. Let x represent the first integer, x+2 represent the srcond integer, and x+ 4

Vsevolod [243]

Given parameters:

First term of the sequence = x

Second term = x + 2

Third term = x + 4

Sum of the first three terms = 72

Unknown:

First term of the sequence = ?

Solution:

The sum of the first three terms is unknown;

(x) + (x + 2) + (x + 4) = 72

Solve for x;

x + x + 2 + x + 4 = 72

3x + 6 = 72

3x = 72 - 6

3x = 66

x = $\frac{66}{3}$ = 22

The first term of the sequence is 22

5 0

2 years ago

Lois wants to send a box of oranges to a friend by mail. the box of oranges cannot exceed a mass of 10 kg. if each orange has a

-Dominant- [34]

No. of Oranges = Total Mass/Mass of one orange
IF only the mass of oranges is considered(not the box)

So, No. of oranges = 10*1000g/200g
= 50
So answer is 50 oranges.

3 0

2 years ago

Math help please,,, thank u uwu!

Svetlanka [38]

Answer:

AC=BD

CAD=CBD

ACB=ADB

Step-by-step explanation:

You're essentially looking for anything of equal proportions. Obviously, your circle is split by several lines, and each side is symmetric. Since you know this, it's simply a matter of identifying one element then finding its symmetric match.

Follow the lines and trace the path with your finger for each question. If you do this, you'll see that AC=BD is an answer that involves a symmetric pair, because these two are equal distances and equal (but opposite) in placement.

Continuing with this method, keep track of the parts of the triangles you trace. With CAD=CBD, you trace across a hypotenuse, a leg, and a base in BOTH, making this true.

Continuing further with ACB=ADB, you trace across a hypotenuse, a leg, and a base with both AGAIN, making this true.

With AB=CD, this is obviously incorrect. You can't jump between points.

7 0

3 years ago

Read 2 more answers

Use the figure to the right to find the value of PT. T is the midpoint of PQ.

vichka [17]

Answer:

Step-by-step explanation:

Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.

Therefore:

$5x + 2 = 7x - 6$