Answer:
Pauline reflected the original figure over the x-axis:
The coordinates of point B will be (4,3)
Carl reflected the original figure over the y-axis:
The coordinate of points B will be (-4,-3)
Answer:
90
60
5
-10
-25
-45
Step-by-step explanation:
Do the biggest number. Then count down. When you get to negative number the smallest negative is the biggest number because it is closer to zero.
19. What you know is that HK+KJ = HJ. If HJ = 25, the sum of the two equations will equal this length.
x-5+5x-12=25 First, combine your like terms. You will end up with 6x-17=25. Add the opposite of -17 to both sides. 6x = 42 Divide both sides by 6. x = 7. Substitute x=7 for your original expression of x-5, 7-5=2
20. (5x-6)/2 = x+6 Multiply each side by 2. 5x-6 = 2x +12 Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well. 3x = 18 Finally divide each side by 3. x=6 To find the length of the remaining segment, substitute this value into (5x-6)/2. This results in each side equaling a distance of 12.
21. On the number line, the distance of FG is 16 units. If the distance of FP is 1/4 of FG, you would simply divide 16 by 4. The distance of FP is 4 and P lies at 8 on your number line.
23. The distance of SP is x+4 and ST=4x. Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x. Balance and solve for x, subtract 2x from both sides. 8=2x Divide each side by 4, 8/4 = 4x/4 resulting in x=2. If ST equals 4x, substitute and solve, 4(2) = 8
A part of a line that connects two endpoints I believe
When calculating accrued interest over several years that compounds annually, you must calculate a new principle each year, adding the accrued interest from the previous year. At the beginning of the new interest period, all the accrued interest is added to the principal which forms a new principle figure that the interest is then counted on.
