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klasskru [66]
1 year ago
12

Solve negative four and one fifth ÷ two and one fourth.

Mathematics
1 answer:
goldfiish [28.3K]1 year ago
6 0

Answer:

  • B. negative one and 39 over 45

Step-by-step explanation:

Convert this into expression:

  • negative four and one fifth ÷ two and one fourth
  • - 4 1/5 ÷ 2 1/4

<h3>Step 1</h3>

Convert each to improper fraction:

  • - 4 1/5 = - 21/5
  • 2 1/4 = 9/4

<h3>Step 2</h3>

Divide the fractions:

- 21/5 ÷ 9/4  =

- 21/5 × 4/9 =

- 84 / 45 =

- 1 13/15

The matching choice is B.

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3 years ago
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How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
Find (ƒ + g)(x) ƒ(x) = 6x2 + 3x + 1 g(x) = 2x2 – 9
gavmur [86]

Answer:

8x² + 3x - 8

Step-by-step explanation:

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On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function C
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3 0
2 years ago
If the standard deviation is 7.3kg, what is the variance?
sasho [114]

Answer:

The variance is 53.29 kg²

Step-by-step explanation:

The standard deviation is the square root of the variance.

So

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S(X) = 7.3

So

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V(X) = 53.29

The variance is 53.29 kg²

6 0
3 years ago
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