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miskamm [114]
3 years ago
14

What should be done so that the expression will have a value of 10? 12 - 2 + 22 ÷ 8 Add parentheses around 2 + 2. Add parenthese

s around 12 - 2. Add parentheses around 2 2 ÷ 8. Nothing needs to be done.
Mathematics
1 answer:
mariarad [96]3 years ago
4 0

12-2+22/8 (=12.75 so the option of doing nothing isn't right)

12-(2+2)2/8 (=11 so that option is gone)

(12-2)+22/8 (=12.75 so that option is gone as well)

12-2+(22/8) (=12.75 So that's gone as well)

?????

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Read 2 more answers
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

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3 years ago
I don’t understand this question. Can anyone help? I need answers ASAP. Thanks for all the help
zavuch27 [327]

There's some unknown (but derivable) system of equations being modeled by the two lines in the given graph. (But we don't care what equations make up these lines.)

There's no solution to this particular system because the two lines are parallel.

How do we know they're parallel? Parallel lines have the same slope, and we can easily calculate the slope of these lines.

The line on the left passes through the points (-1, 0) and (0, -2), so it has slope

(-2 - 0)/(0 - (-1)) = -2/1 = -2

The line on the right passes through (0, 2) and (1, 0), so its slope is

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The slopes are equal, so the lines are parallel.

Why does this mean there is no solution? Graphically, a solution to the system is represented by an intersection of the lines. Parallel lines never intersect, so there is no solution.

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Step-by-step explanation:

hope this helped you :)) !!

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