All categories

4 years ago

Find (ƒ + g)(x) ƒ(x) = 6x2 + 3x + 1 g(x) = 2x2 – 9

Mathematics

1 answer:

gavmur [86]4 years ago

8 0

Answer:

8x² + 3x - 8

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x) = 6x² + 3x + 1 + 2x² - 9 = 8x² + 3x - 8

You might be interested in

Use either point Bor point Cto find the lengths of the

zalisa [80]

Please don’t click link it’s a hacker !!!

8 0

3 years ago

Round to the nearest 10th

german

Answer:

look below

Step-by-step explanation:

To round a number to the nearest tenth , look at the next place value to the right (the hundredths). If it's 4 or less, just remove all the digits to the right. If it's 5 or greater, add 1 to the digit in the tenths place, and then remove all the digits to the right.

5 0

3 years ago

In a physics laboratory experiment, a coil with 200 turns en-closing an area of 12 cm2 is rotated in 0.040 s from a position whe

Alla [95]

Answer: (a) Magnetic flux before rotation is 7.2 × 10^-8 Wb and magnetic flux after rotation is 0

(b) The average emf induced in the coil is 3.6×10^-4 V

Step-by-step explanation:

Here is the complete question:

In a physics laboratory experiment, a coil with 200 turns en-closing an area of 12 cm2 is rotated in 0.040 s from a position where its plane is perpendicular to the earth’s magnetic field to a position where its plane is parallel to the field. The earth’s magnetic field at the lab location is 6.0×10^−5T. (a) What is the total magnetic flux through the coil before it is rotated? After it is rotated? (b) What is the average emf induced in the coil?

Step-by-step explanation: Please see the attachments below

7 0

3 years ago

Whats the answer to this?

mars1129 [50]

Answer:

15 degrees

X is an Acute Angle

Step-by-step explanation:

x+ 75 = 90

x =15

4 0

3 years ago

An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20

expeople1 [14]

Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

$\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|$

From the table

$\sum f_i =149+x+y$

Here, n = 200

n/2 = 100

Lower Class Boundary of the median class, l=60

Frequency of the median class(f) =66

Cumulative Frequency before the median class, f=42+x

Class Width, h=10

$Median = l + \dfrac{\dfrac{n}{2} - c.f }{f} \times h$

$70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8$

200=149+x+y

200=149+8+y

y=200-(149+8)

y=43

Hence, the missing frequencies are x = 8 and y = 43.

8 0

3 years ago