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tankabanditka [31]
1 year ago
6

A crab moves at a speed of 0.14 kilometers per hour. How far can it travel for 0.25 hours?

Mathematics
2 answers:
devlian [24]1 year ago
8 0

Answer:

0.14×0.25= 0.035 KM

so it can travel 0.035KM in 0.25 hr

sergiy2304 [10]1 year ago
3 0

Answer:

0.035 kilometers

Step-by-step explanation:

Proportions:

0.14 kilometers ⇒ 1 hour

A kilometers ⇒ 0.25 hour

A = 0.14 kilometers * 0.25 hour / 1 hour

A = 0.035 kilometers

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HELP PLSSSSS
ludmilkaskok [199]

Answer:

a=21

AB=23.9

BC=19.5

CD=(23.9)

AD=19.5

Step-by-step explanation:

Each pair of parallel sides are equal in a parallelogram. Sense both pairs use the same variable we can just choose the easiest to solve which would be:

a-1.5=19.5

add 1.5 to both sides

a=21

now substitute 21 in for a in each equation.

AB=CD so

AB=23.9

BC=AD so

BC=19.5

CD=(21)+2.9 so

CD=(23.9)

AD is given so

AD=19.5

4 0
2 years ago
May someone please help me?
otez555 [7]

Answer:

x=8°

y=29°

Step-by-step explanation:

vertically opposite angles are equal

so 5x+9°=y+20°

therefore 5x-y=11°

Alternate angles are equal

so 4x+17°=y+20°

therefore 4x-y=3°

equation 1....... 5x-y=11°

equation 2......4x-y=3°

using elimination method x=8°

y=29°

5 0
3 years ago
3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
What is the derivative of y=ln(ln(x))?
Marysya12 [62]
Y=ln(ln(x)) y'=(1/x)/Ln(x)=1/xln(x)
7 0
3 years ago
Simplify 4(b-6)+19 ?
Digiron [165]

Answer:

4b -5

Step-by-step explanation:

Perform the indicated multiplication first:  4b - 24 + 19.  Next, combine like terms, obtaining 4b -5 (answer)

4 0
3 years ago
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