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german
2 years ago
7

Solve for n: (n+4)/10 = (n-8)/2

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
6 0

Answer: n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

multiply both sides by 10

n+4 = (n-8)/2*10

cancel

n+4=(n-8)*5

n+4=5(n-8)

multiply

n+4=5n-40

subtract both sides by 5n

n-5n+4=-40

subtract both sides by 4

n-5n=-40-4

subtract the like terms

-4n=-44

cancel the negatives

4n=44

divide each side by 4

n=11

nalin [4]2 years ago
4 0

Answer:

n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

(n+4) * 2 = 10 * ( n-8)

Distribute

2n+8 = 10n -80

Subtract 2n from each side

2n+8-2n = 10n-80-2n

8 = 8n-80

Add 80 to each side

8+80= 8n-80+80

88 = 8n

Divide each side by 8

88/8 = 8n/8

11 = n

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Given,

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First find the value of x

\sf \: GK \:  = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x =  - 15 - 10 \\ \sf - x =  - 25 \\  \sf \: -  >   \boxed{\bf \: x = 25}

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\sf3x - 15 \\  \sf= 3(25) - 15 \\  \sf=7 5 - 15 \\     = \boxed{\bf \: 60}

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