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german
1 year ago
7

Solve for n: (n+4)/10 = (n-8)/2

Mathematics
2 answers:
Karo-lina-s [1.5K]1 year ago
6 0

Answer: n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

multiply both sides by 10

n+4 = (n-8)/2*10

cancel

n+4=(n-8)*5

n+4=5(n-8)

multiply

n+4=5n-40

subtract both sides by 5n

n-5n+4=-40

subtract both sides by 4

n-5n=-40-4

subtract the like terms

-4n=-44

cancel the negatives

4n=44

divide each side by 4

n=11

nalin [4]1 year ago
4 0

Answer:

n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

(n+4) * 2 = 10 * ( n-8)

Distribute

2n+8 = 10n -80

Subtract 2n from each side

2n+8-2n = 10n-80-2n

8 = 8n-80

Add 80 to each side

8+80= 8n-80+80

88 = 8n

Divide each side by 8

88/8 = 8n/8

11 = n

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Step-by-step explanation:

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2 years ago
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
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Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

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