[ Answer ]
[ Explanation ]
- Simplify / Solve: (5 ÷ 5) ÷ 5 · ( - 5)
--------------------------------
( - 5)
- Apply Rule ( = 1): = 1
( - 5)
1 · ( - 5) = 20
=
20 ÷ 5
= 4
<span>The legs of a right triangle are 12 cm and 16 cm. What is the length of the hypotenuse? 15 cm 17 cm 20 cm 28 cm
answer - 20
Find the length of the unknown side. Round your answer to the nearest tenth. Image of a right triangle with a leg of 4, hypotenuse of 18, and second leg unknown. 16.5 17.5 18.5 22.0
answer - 17.5
Find the length of the unknown side. Round your answer to the nearest whole number. Image of a right triangle with legs labeled 5 inches each and hypotenuse unknown. 7 in 10 in 25 in 50 in
answer - 7
The hypotenuse of a right triangle is 26 mm. One leg of the right triangle is 10 mm. What is the length of the other leg?
answer - 27.86mm</span>
Recall that given the equation of the second degree (or quadratic)
ax ^ 2 + bx + c
Its solutions are:
x = (- b +/- root (b ^ 2-4ac)) / 2a
discriminating:
d = root (b ^ 2-4ac)
If d> 0, then the two roots are real (the radicand of the formula is positive).
If d = 0, then the root of the formula is 0 and, therefore, there is only one solution that is real and of multiplicity 2 (it is a double root).
If d <0, then the two roots are complex and, in addition, one is the conjugate of the other. That is, if one solution is x1 = a + bi, then the other solution is x2 = a-bi (we are assuming that a, b, c are real).
One solution:
A cut point with the x axis
Two solutions:
Two cutting points with the x axis.
Complex solutions:
Does not cut to the x axis
9514 1404 393
Answer:
x = 1/4(y -4)² +7
Step-by-step explanation:
A parabola can have the equation ...
x = 1/(4p)(y -k)² +h
where the vertex is (h, k), and the vertex-to-focus distance is p.
The vertex is halfway between the focus and directrix, so has coordinates ...
((8, 4) +(6, 4))/2 = (7, 4)
The distance from the vertex to the focus is 8-7 = 1, so the equation can be written ...
x = 1/4(y -4)² +7