Write the ratio 2/7 to 4 as a fraction in simplest form

What is the rate of return when 35 shares of Stock A, purchased for $20/share, are sold for $815? The commission on the sale is

wariber [46]

Cost price:-

$\\ \sf\longmapsto 35\times 20$

$\\ \sf\longmapsto 700$

Commision=$6
Total sold price=815+6=823$

Now

Return=823-700=123

Rate of return

$\\ \sf\longmapsto \dfrac{123}{700}\times 100$

$\\ \sf\longmapsto \dfrac{123}{7}$

$\\ \sf\longmapsto 17.5\%$

7 0

2 years ago

Read 2 more answers

A street that is 360 feet long is covered in snow city workers are using a snow plow to clear the street a tire on the snow plow

belka [17]

Answer:

Radius of tire=0.58 meter

Step-by-step explanation:

as we know that the

Circumference of the tire=2*3.14*r

and it needs to rotate 30 times to cover the street distance of 360 feet

So, the below equation would be used to find the radius of tire in the meters

360/3.28084=30*2*3.14*r

r=0.5824203822 meters

Hence

$Radius=0.58 meter$

3 0

2 years ago

Fractions equivalent to - 9/16

kiruha [24]

Answer:

Equivalent Fractions for 9/16: There are infinity equivalent fractions to 916. See some examples: 916, 1832, 2748, 3664, 4580, 5496, 63112, 72128, 81144, 90160, 99176, 108192, 117208, 126224, 135240, 144256, 153272, 162288, 171304

Step-by-step explanation:

NOT my answer, got it from g0ogle..

5 0

3 years ago

Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t

Amanda [17]

Answer:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

$df = n-1= 22-1=21$

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

$\bar X=33.9$ represent the sample mean

$s=4.1$ represent the sample standard deviation

$n=22$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing we got:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

Now we can calculate the critical value but first we need to find the degreed of freedom:

$df = n-1= 22-1=21$

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0

3 years ago

Find the probability that when a couple has four children, at least one of them is a girl. (Assume that boys and girls are equ

AveGali [126]

Answer:

0.9375 = 93.75% probability that at least one of the four children is a girl.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have the following sample space

In which b means boy, g means girl

b - b - b - b

b - b - b - g

b - b - g - b

b - b - g - g

b - g - b - b

b - g - b - g

b - g - g - b

b - g - g - g

g - b - b - b

g - b - b - g

g - b - g - b

g - b - g - g

g - g - b - b

g - g - b - g

g - g - g - b

g - g - g - g

Total outcomes

There are 16 total outcomes(size of the sample space)

Desired outcomes

Of these outcomes, only 1(b - b - b - b) there is not a girl.

So the number of desired outcomes is 15.

Probability:

$P = \frac{15}{16} = 0.9375$

0.9375 = 93.75% probability that at least one of the four children is a girl.

7 0

3 years ago