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Alexxx [7]
1 year ago
14

Calculate the average rate of change in temperature between 8:00 am and 11:00 am. round your answer to two decimal places. a. 4.

33° c. 4.64° b. 5.36° d. 3.26°
Mathematics
1 answer:
sleet_krkn [62]1 year ago
7 0

The average rate of change of temperature between 8:00 and 11:00 is given as 4.33 degrees.

<h3>How to solve for the rate of change of temperature</h3>

Now we are to find the change in temperature between the two hours stated in the question.

These hours are 8 00 and also 11 00.

Now at 8.00 the temperature is at 82

Then at 11 00 the temperature is at 95

Then the rate of change between these temperatures would be given as

95 - 82 / 3 hours

we have three hours in between both periods

= 4.33

the average rate of change in temperature between 8:00 am and 11:00 am is 4.33

Complete question

Solve the problem.

7)

7) The following table gives the outside temperature in degrees Fahrenheit on a winter day in Death Valley, California.

Time | 7:00 am 8:00 am | 9:00 am | 10:00 am | 11:00 am

Temperature (°F)||

78

82

85

91

95

Calculate the average rate of change in temperature between 8:00 am and 11:00 am. Round your answer to two decimal places when appropriate.

A) 5.36°F

B) 3.26°F

C) 4.64°F

D) 4.33°F

Read more on temperature here: brainly.com/question/25677592

#SPJ1

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Answer:

a. independent = number of days

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f(x) = number of miles

c. f(x)=850

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Step-by-step explanation:

a. the number of miles depends on number of days because more days equals more miles traveled.

b. Idk u need y or f(x) but just switch to one u need.

c. 340 × 2.5 = 850

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4 0
3 years ago
In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee
kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that x^{2} =pz

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and  Δ ADB in the attached file , ∠A is common in both triangles

                                                                     and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

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Cross multiply

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7 0
3 years ago
In The autumn 40% of the leaves on a tree are yellow and 24% of them are green the remaining 72 leaves are half yellow how many
Charra [1.4K]

Percentage of yellow leaves on a tree during Autumn = 40%

Percentage of green leaves on a tree during Autumn = 24%

Percentage of half yellow leaves on the tree during Autumn :

=  \tt100 - 40 + 24

= \tt 100 - 64

= \tt 36 \%Thus, the percentage of half yellow leaves on the tree during Autumn = 36%

Number of half yellow leaves on the tree = 36%

Let the total number of leaves on the tree be x.

Which means :

=  \tt36 \% \: of \: x = 72

=  \tt \frac{36}{100}  \times x = 72

=  \tt \frac{36 \times x}{100}  = 72

=  \tt \frac{36x}{100}  = 72

= \tt 36x = 72 \times 100

=  \tt36x = 7200

= \tt x =  \frac{7200}{36}

\color{plum} =  \tt \: x = 200

Thus, total number of leaves on the tree = 200

Number of yellow leaves on the tree :

=  \tt40 \% \: \:  of \: \:  200

=  \tt \frac{40}{100}  \times 200

= \tt   \frac{40 \times 200}{100}

= \tt  \frac{8000}{100}

\color{plum}  \tt = 80 \: yellow \:  \: leaves

Thus, total number of yellow leaves on the tree = 80

Number of green trees on the tree :

=  \tt24 \% \:  \: of \:  \: 200

= \tt  \frac{24}{100} \times 200

= \tt  \frac{24 \times 200}{100}

=  \tt \frac{4800}{100}

\color{plum} = \tt 48 \: green \:  \: leaves

Thus, the total number of green leaves on the tree = 48

Since the sum of all types of leaves form 200[80+48+72=200], we can conclude that we have found out the correct number of each type of leaf.

▪︎Therefore, <em>the total number of leaves on the tree = 200</em>

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