All categories

2 years ago

What is the value of y in the triangle?

Mathematics

1 answer:

Readme [11.4K]2 years ago

8 0

Answer:

• From trigonometric ratios:

${ \rm{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\$

→ theta is 41°

→ opposite is y

→ hypotenuse is 26 ft

${ \tt{ \sin(41) = \frac{y}{26} }} \\ \\ { \tt{y = 26 \sin(41) }} \\ \\ { \boxed{ \tt{ \: y = 17.06 \: \: ft}}}$

You might be interested in

Below are two parallel lines with a third line intersecting them.

irina1246 [14]

Answer: x=56°

The opposite angle of 56° and the opposite angle of ∠x are alternate angles.

5 0

2 years ago

Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

kari74 [83]

Answer:

C. $\frac{1}{18}$

Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

Solution:

Sample space for sum of cards when two cards are drawn at random is $\{(1,1),(1,2),(1,3)......(6,6)\}$

total number of possible cases $=36$

Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

$p(\text{A})$ $=\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}$

$p(\text{A})=\frac{5}{36}$

Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

Now,

probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

3 0

2 years ago

The linear equation y = 400 + 50x represents the total cost, y , per hour, x , for a lawyer at a law firm. The lawyer charges a

earnstyle [38]

Answer:

453

Step-by-step explanation:

because we multiply the value with the equation

5 0

2 years ago

One of the factors of 34 is chosen at random. What is the probability that the factor is itself a two digit number?

solong [7]

A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?

The positive whole-number factors of 30 are:

1, 2, 3, 5, 6, 10, 15 and 30.

So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that

P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors

=38=3×.125=.375

8 0

2 years ago

What is the solution for the system of equations {9x+8y=3 6x−12y=−11?

lions [1.4K]

Answer:

( - $\frac{1}{3}$ , $\frac{3}{4}$ )