Answer: use mathaway it’s the best
Step-by-step explanation:
Hope it helps u
Answer:
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Step-by-step explanation:
given that after comparing response times between the audio and picture portions of the MIT test, the t-test resulted in a t-value of 2.97.
test statistic t = 2.97
Sample size n =250
Critical value of t at 95% is 1.96
We find that test statistic absolute value is greater than 1.96
So p value would be less than 0.05
This implies that null hypothesis stands in the rejected region.
So reject null hypothesis would be correct conclusion. Sample size cannot be said to be small as more than 30 itself is a good sample size.
e. reject the null hypothesis the p value is less than 0.05. therefore the difference is significant.
Answer:
All work is shown and pictured
Answer:
![\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In order to find out the resulting matrix, we will have to multiply the identity matric and the scalar 3:
The 3x3 identity matrix is:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
Multiplying with scalar 3:
![3\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
The scalar will be multiplied by each element of the matrix.
Multiplying zeros with scalar 3 will give us zero. So the resulting matrix will be:
![\left[\begin{array}{ccc}3*1&0&0\\0&3*1&0\\0&0&3*1\end{array}\right] = \left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%2A1%260%260%5C%5C0%263%2A1%260%5C%5C0%260%263%2A1%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
So the resultant matrix will be a scalar matrix with 3 at diagonal positions..
The average low temperature is -10.
-8+(-13)+(-4)+(-9)+(-16)= -50/5=-10
