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1 year ago

Jorge, sandra, danny, and valeria each mowed lawns after school and on the

Mathematics

1 answer:

Ronch [10]1 year ago

8 0

Jorge mowed 18 lawns.

Let the number of lawns mowed by Jorge =x

So according to the question

Number of lawns mowed by sandra = x/3

Number of lawns mowed by Danny =x/2

Number of lawns mowed by Valeria =16

sum of total lawns mowed = lawns mowed by Jorge + lawns mowed by sandra + lawns mowed by Danny + lawns mowed by Valeria.

$x+\frac{x}{3} +\frac{x}{2} +16=49$

taking LCM as 6 and solving further we get

$\frac{6x+2x+3x+96}{6} =49$

By cross Multiplying we get

11x+96=294

11x=198

Solving further for x,

x=198/11

x=18

Therefore, the number of lawns mowed by Jorge is 18 .

Learn more about Ratio here brainly.com/question/15271657

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<h3>How to calculate temperature?</h3>

The quantity or amount of radiation contained in material or item, as measured by a temperature or sensed by touch and stated on a numerical scale.

The temperature T of a ball bearing is inverse to the length first from the origin, which we consider to be the center of the ball. The temperature at the exact location

(x, y, z) is a point on the sphere, the temperature at this point is given by

$T(x,y,z)= \dfrac{k}{(x^2 +y^2+z^2)^{1/2}}$

Where k is constant, then we have

T(1, 2, 2) = k/3 = 170

k = 510

$T(x,y,z)= \dfrac{510}{(x^2 +y^2+z^2)^{1/2}}$

Then we have

$\rm \triangledown T = \left ( -\dfrac{510x}{(x^2 +y^2+z^2)^{1/2}}, -\dfrac{510y}{(x^2 +y^2+z^2)^{1/2}}, \dfrac{510z}{(x^2 +y^2+z^2)^{1/2}} \right )\\\\\\\triangledown T (1, 2, 2) = -\dfrac{510}{27} (1, 2, 2) =-\dfrac{170}{9} (1, 2, 2)$

Then the direction will be from (1, 2, 2) to (4, 3, 5) will be (3, 1, 3)

So u = (3/√19, 1/√19, 3/√19)

Then we get

$\rm \triangledown T \cdot u = \dfrac{-170}{9}(1, 2, 2) \cdot \left (\dfrac{3}{\sqrt{19}}, \dfrac{1}{\sqrt{19}}, \dfrac{3}{\sqrt{19}} \right )\\\\\\\triangledown T \cdot u = - \dfrac{170}{9\sqrt{19}} (3 + 2 + 6)\\\\\\\triangledown T \cdot u = -\dfrac{1870}{9\sqrt{19}}$

The direction of the greatest inverse in the temperature is given by any vector parallel to and having the same direction $\triangledown$ T. (-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.