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Hunter-Best [27]

3 years ago

11

Help pls this is my first question on here and I need help with this pls. I will give you the brainliest and a thanks!! :)) Can

you do 1 and 4 thanks!! :)))

1 answer:

docker41 [41]3 years ago

4 0

Answer:

1. 18.85in

4. 25.13m

Step-by-step explanation:

I got you

So to find the circumference of any circle we use the equation 2pi(r)

2(3.1415)(3)= 18.85in for the first one because radius is half of the diameter which is 6 so half of 6 is 3

For 4. 4m is actually the radius so just plug that into the equation 2pi(4)=25.13m

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If i get paid 7$ plus 15% how much is that

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- If you divide a number by four and then add six, you<br> get eighteen. What is the number?

stiks02 [169]

Answer:

48

Step-by-step explanation:

Create an equation to represent this, where x is the unknown number.

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Step-by-step explanation:

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3 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation $A=45e^{-0.05t}$ .

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate $A=15$ and solve for t as:

$15=45e^{-0.05t}$

$\frac{15}{45}=\frac{45e^{-0.05t}}{45}$

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Now we will switch sides:

$e^{-0.05t}=\frac{1}{3}$

Let us take natural log on both sides of equation.

$\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})$

$-0.05t\cdot (1)=\text{ln}(\frac{1}{3})$

$-0.05t=\text{ln}(\frac{1}{3})$

$t=\frac{\text{ln}(\frac{1}{3})}{-0.05}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}$

$t=-\text{ln}(\frac{1}{3})\cdot 20$

$t=-(\text{ln}(1)-\text{ln}(3))\cdot 20$

$t=-(0-\text{ln}(3))\cdot 20$

$t=20\text{ln}(3)$

Therefore, it will take $20\text{ln}(3)$ years for area of the glacier to decrease to 15 square kilo-meters.

6 0

3 years ago

Graph this quadratic funtion f(x)=x^2+1

lawyer [7]

Let's examine the given function first:
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Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.

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