The amount invested at 11% is $5,000
The amount invested in stock is $14,000
What is the net profit on both investments?
The profit of each investment is the rate of return or loss multiplied by the amount invested
Let us assume that x was invested at 11% and the remaining 19000-x was invested at a loss rate of 3%
net profit=(11%*x)+(19000-x)*-3%
net profit=130
130=(11%*x)+(19000-x)*-3%
130=0.11x-570+0.03x
130=0.14x-570
130+570=0.14x
700=0.14x
x=700/0.14
x=$5,000
Amount invested in stock=19000-x
Amount invested in stocks=19000-5000
Amount invested in stocks=$14,000
Find out more about combined investments on:brainly.com/question/2166053
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The question is incomplete, as the depth of the hook isn't given in the question. However, using a proposed depth for the hook, we could give a stepwise solution to the exercise. 
Answer:
Kindly check explanation 
Step-by-step explanation:
If given a hook depth of 6 meters, and a distance of 8 m(fishing line from hook) at the the Same depth, then the distance between rose and the fish, x can be calculated, using the relation.
Hypotenus² = opposite² + adjacent²
(refer to attached picture)
x² = 6² + 8²
x² = 36 +. 64
x² = 100
x = sqrt(100)
x = 10 meters
You can use the actual depth value to obtain the actual solution to your question. 
 
        
             
        
        
        
Answer:
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
A & B
Step-by-step explanation:
A is spot-on because of the use of distributive property. B by the use of like terms.
 
        
             
        
        
        
Answer:
as a fraction it could be 3/5 
Step-by-step explanation:
but as a decimal it would be 0.6