Its impossible to solve this, but i got -47
Answer:
what is the question?
Step-by-step explanation:
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
expected profit is - $0.50
Step-by-step explanation:
1 $(7.00) 0.166666667 $(1.17)
2 $(7.00) 0.166666667 $(1.17)
3 $1.00 0.166666667 $0.17
4 $1.00 0.166666667 $0.17
5 $1.00 0.166666667 $0.17
6 $8.00 0.166666667 $1.33
$(0.50)
Answer:

Step-by-step explanation:
That would be a divide by 5: 