Uhhh 18?? 9+9, 10+8, 7+11, 6+12, 5+13, 4+14, 3+15, 2+16, 1+17
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
<em>Answer:</em>
<u>Tony</u> has 45 dollars
<u>Milan</u> has 15 dollars
<u>Lucy</u> has 25 dollars
<em>Explanation:</em>
<u>Let </u><u><em>x</em></u><u> represent the amount of money Milan has in his wallet.</u>
TONY: 3x
MILAN: x
LUCY: x+10
<u>Lucy, Milan, and Tony have a total of $85 in their wallets. Hence, the following equation.</u>
<u />
3x+x+x+10=85
5x+10=85
5x=75
x=75/5
x=15
Tony has 45 dollars (3*15=45)
Milan has 15 dollars (x=15)
Lucy has 25 dollars (10+15=25)
First, you need to move 2 to the other side. You accomplish this by adding 2 to 1. You have y>3. Since your variable is smaller than 3, draw an open circle on the 3 mark and a squiggly line left of 3.