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MrRissso [65]
2 years ago
10

Which adaptation of eap utilizes eap-mschapv2 inside of an encrypted tls tunnel?

Computers and Technology
1 answer:
cluponka [151]2 years ago
7 0

Main Answer:

<h3>which adaptation of eap utilizes eap mschapv2 inside of an encrypted tls tunnel? <u>protected (EAP)</u></h3>

sub heading:

what is meant by protected( EAP)?

Explanation:

1.The protected extensible authentication protocal also known as protected (EAP).

2.transport layer security tunnen

Refference link :

https//brainly.com

Hashtag:

#SPJ4

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Convert 192.16.3.1 to a Binary number
jenyasd209 [6]
Converting a decimal number into binary would be:

192/2= 96   remainder=0  
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48/2=24     remainder=0
24/2=12      remainder=0
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3/2=1          remainder=1
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For 16
16/2=8     remainder=0
8/2=4      remainder=0
4/2=2       remainder=0
2/2=1         remainder=0
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For 3
3/2=1       remainder=1
1/2= 0         remainder=1
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For 1
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The binary number would be:  
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Jamie takes part in a quiz competition. she is asked to name the total number of combinations that the bits 1 and 0 will have in
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The answer is A 

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6 0
3 years ago
Read 2 more answers
Using vectors: Create a vector of integers of size 100, with random numbers ranging from 1 to 50. Print out these 100 numbers in
zysi [14]

Answer:

In C++

#include <iostream>  

#include <vector>  

using namespace std;  

int main() {  

   vector<int> Vector1, Vector2, Vector3; int total2 = 0, total3 = 0, count2 = 0, count3 =0;

   srand((unsigned)time(NULL));

   int total = 0;

   for (int kt =0; kt < 100; kt++){

       int b = rand() % 50 + 1;

       Vector1.push_back(b);

       cout << Vector1[kt] << " ";

       total+=b;    }

   double avg = (total * 1.0)/100.0;

   cout<<endl<<"Overall Average: "<<avg<<endl;

   for (int kt =0; kt < 100; kt++){

       if(Vector1[kt]>=1 && Vector1[kt]<=30){

           Vector2.push_back(Vector1[kt]); total2+=Vector1[kt]; count2++;        }

       else{

           Vector2.push_back(Vector1[kt]); total3+=Vector1[kt]; count3++;        }    }

       double avg1 = (total2 * 1.0)/count2, avg2 = (total3 * 1.0)/count3;

       cout<<"Average 1 - 30: "<<avg1<<endl;

       cout<<"Average 31 - 50: "<<avg2<<endl;

       double avg3 = (avg1 + avg2)/2;

       cout<<"Average of Average: "<<avg3<<endl;

       if(avg == avg3){            cout<<"Both average are equal";        }

       else{        cout<<"Both average are not equal";        }

   return 0;}

Explanation:

See attachment for complete question where comments were used to explain each line

Download cpp
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kodGreya [7K]

Answer:

I believe its C.

Explanation:

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4 years ago
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