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larisa86 [58]
3 years ago
6

Science is a body of knowledge that extends back to Select one: a. the time of Galileo. b. Italy in the 16th century. c. Greece

in the 7th century B.C. d. humankind's beginnings.
Computers and Technology
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:

I believe its C.

Explanation:

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enyata [817]
The user requests an application to run by making a system call to get it started
6 0
3 years ago
Read 2 more answers
This project must target a Unix platform and execute properly on our CS1 server.
sweet-ann [11.9K]

Answer:

hope this helps ,if it did pls do consider giving brainliest

Explanation:

// Java program for implementation of FCFS scheduling

import java.text.ParseException;

class GFG {

// Function to find the waiting time for all

// processes

static void findWaitingTime(int processes[], int n,

int bt[], int wt[]) {

// waiting time for first process is 0

wt[0] = 0;

// calculating waiting time

for (int i = 1; i < n; i++) {

wt[i] = bt[i - 1] + wt[i - 1];

}

}

// Function to calculate turn around time

static void findTurnAroundTime(int processes[], int n,

int bt[], int wt[], int tat[]) {

// calculating turnaround time by adding

// bt[i] + wt[i]

for (int i = 0; i < n; i++) {

tat[i] = bt[i] + wt[i];

}

}

//Function to calculate average time

static void findavgTime(int processes[], int n, int bt[]) {

int wt[] = new int[n], tat[] = new int[n];

int total_wt = 0, total_tat = 0;

//Function to find waiting time of all processes

findWaitingTime(processes, n, bt, wt);

//Function to find turn around time for all processes

findTurnAroundTime(processes, n, bt, wt, tat);

//Display processes along with all details

System.out.printf("Processes Burst time Waiting"

+" time Turn around time\n");

// Calculate total waiting time and total turn

// around time

for (int i = 0; i < n; i++) {

total_wt = total_wt + wt[i];

total_tat = total_tat + tat[i];

System.out.printf(" %d ", (i + 1));

System.out.printf(" %d ", bt[i]);

System.out.printf(" %d", wt[i]);

System.out.printf(" %d\n", tat[i]);

}

float s = (float)total_wt /(float) n;

int t = total_tat / n;

System.out.printf("Average waiting time = %f", s);

System.out.printf("\n");

System.out.printf("Average turn around time = %d ", t);

}

// Driver code

public static void main(String[] args) throws ParseException {

//process id's

int processes[] = {1, 2, 3};

int n = processes.length;

//Burst time of all processes

int burst_time[] = {10, 5, 8};

findavgTime(processes, n, burst_time);

}

}

// Java program to implement Shortest Job first with Arrival Time

import java.util.*;

class GFG {

static int[][] mat = new int[10][6];

static void arrangeArrival(int num, int[][] mat) {

for (int i = 0; i < num; i++) {

for (int j = 0; j < num - i - 1; j++) {

if (mat[j][1] > mat[j + 1][1]) {

for (int k = 0; k < 5; k++) {

int temp = mat[j][k];

mat[j][k] = mat[j + 1][k];

mat[j + 1][k] = temp;

}

}

}

}

}

static void completionTime(int num, int[][] mat) {

int temp, val = -1;

mat[0][3] = mat[0][1] + mat[0][2];

mat[0][5] = mat[0][3] - mat[0][1];

mat[0][4] = mat[0][5] - mat[0][2];

for (int i = 1; i < num; i++) {

temp = mat[i - 1][3];

int low = mat[i][2];

for (int j = i; j < num; j++) {

if (temp >= mat[j][1] && low >= mat[j][2]) {

low = mat[j][2];

val = j;

}

}

mat[val][3] = temp + mat[val][2];

mat[val][5] = mat[val][3] - mat[val][1];

mat[val][4] = mat[val][5] - mat[val][2];

for (int k = 0; k < 6; k++) {

int tem = mat[val][k];

mat[val][k] = mat[i][k];

mat[i][k] = tem;

}

}

}

// Driver Code

public static void main(String[] args) {

int num;

Scanner sc = new Scanner(System.in);

System.out.println("Enter number of Process: ");

num = sc.nextInt();

System.out.println("...Enter the process ID...");

for (int i = 0; i < num; i++) {

System.out.println("...Process " + (i + 1) + "...");

System.out.println("Enter Process Id: ");

mat[i][0] = sc.nextInt();

System.out.println("Enter Arrival Time: ");

mat[i][1] = sc.nextInt();

System.out.println("Enter Burst Time: ");

mat[i][2] = sc.nextInt();

}

System.out.println("Before Arrange...");

System.out.println("Process ID\tArrival Time\tBurst Time");

for (int i = 0; i < num; i++) {

System.out.printf("%d\t\t%d\t\t%d\n",

mat[i][0], mat[i][1], mat[i][2]);

}

arrangeArrival(num, mat);

completionTime(num, mat);

System.out.println("Final Result...");

System.out.println("Process ID\tArrival Time\tBurst" +

" Time\tWaiting Time\tTurnaround Time");

for (int i = 0; i < num; i++) {

System.out.printf("%d\t\t%d\t\t%d\t\t%d\t\t%d\n",

mat[i][0], mat[i][1], mat[i][2], mat[i][4], mat[i][5]);

}

sc.close();

}

}

7 0
3 years ago
In an organization, several teams access a critical document that is stored on the server. How would the teams know that they ar
ss7ja [257]

Answer:

D. by checking the version history

Explanation:

When you access a document that is stored on the server and it is used by several teams, you can check the version history by going to file, then version history and see version history and in there, you can check all the versions, who edited the file and the changes that have been made. According to this, the answer is that the teams know that they are accessing the latest copy of the document on the server by checking the version history.

The other options are not right because a duplicate copy and taking a backup don't guarantee that you have the latest version of the document. Also, a reporting tool is a system that allows you to present information in different ways like using charts and tables and this won't help to check that you have the latest version of the document.

5 0
3 years ago
Which of the following lists the stages of the four-stroke engine cycle in the correct order of operation?
kvasek [131]
The answer is (a) Intake, Compression, Power, Exhaust.
The fourth-stroke engine cycle or the commonly known as the four cycle is a type of engine that completes four separate strokes while turning a crankshaft. First is the Intake where the piston begins at TDC. Second is the compression where it begins at BDC and the piston compresses the air-fuel mixture for ignition. Third is combustion where the second revolution of the cycle starts. Last is the exhaust where the piston once again returns to TDC from BDC.
6 0
3 years ago
How to add up multiple user inputs for example: If i ask the user How many numbers do you want to add? they say 5 then i out put
Morgarella [4.7K]

Answer:

import java.util.Scanner;

class Main {

 public static void main(String[] args) {

   Scanner scanner = new Scanner(System.in);

   System.out.println("How many numbers do you want to add?");

   int numberOfNumbers = scanner.nextInt();

   int arrayNumbers[] = new int[numberOfNumbers];

   System.out.println("Enter " + numberOfNumbers + " numbers:\n");

   for(int i = 0; i < numberOfNumbers; i++){

     int addToArray = scanner.nextInt();

     arrayNumbers[i] = addToArray;

   }

   int sum = 0;

   for(int j = 0; j < arrayNumbers.length; j++){

     sum+=arrayNumbers[j];

   }

   System.out.println("Sum: " + sum);

 }

}

Explanation:

6 0
2 years ago
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