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Mrac [35]
1 year ago
15

Consider a sequence of transformations where ΔLMN is translated (x, y) → (x − 3, y + 4), reflected across the yaxis, and then re

flected across the x-axis. Predict the effect of the second transformation.
Mathematics
1 answer:
Svetlanka [38]1 year ago
5 0

the effect of the second transformation just is:

(x - 3, y + 4) → (-3 + 4, y + 4)

<h3>What will be the effect of the second transformation?</h3>

Here we have a sequence of transformations, we start with a point (x, y) which we:

  • First, we translate it 3 units to the left and 4 units up.
  • Second, we reflect it across the y-axis
  • Finally, we reflect it across the x-axis.

The second transformation is the first reflection, so we need to see what that reflection does.

First, the translation maps our point from (x, y) into (x - 3, y + 4).

Then, a reflection across the y-axis will only change the sign of the x-component of our point, so the effect of the second transformation just is:

(x - 3, y + 4) → (-3 + 4, y + 4)

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

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A researcher is exploring the notion that there is an economy of scale in raising children. While having one child might add to
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Answer:

The probability is   G  =  85%

Step-by-step explanation:

From the question we are told that

   The percentage of parents that have one child under 18 in their homes is  k = 15%

  The percentage of parents that have two children is  T = 65%

    The percentage of parents that have three or more children is  Y = 20%

Generally the probability that any given family who is selected have two or more children at home is mathematically evaluated as

     G  =  T  +  Y

=>  G  =  65% +  20%

=>  G  =  85%

4 0
4 years ago
Find the center and radius of the circle whose diameter has an endpoint at (-3, -4) and the origin.
Zina [86]

Given end points of diameter,

(x1,y1)=(-3,-4)

(x2,y2)=(0,0)

Now,

the equation of circle is,

(x-x1)(x-x2)+(y-y1)(y-y2)=0

or, (x+3)(x-0)+(y+4)(y-0)=0

or, x^2 +3x +y^2 +4y =0

or, x^2 +y^2 +3x + 4y=0

which is in the form of x^2 +y^2 +2gx +2fy + c=0

where,

g=3/2

h=2

c=0

Now,

radius(r) =  \sqrt{ {g}^{2}  +  {f}^{2} - c  } \\  =  \sqrt{ \frac{ {3}^{2} }{ {2}^{2} } +  {2}^{2}  - 0 }  \\  =  \sqrt{ \frac{9}{4}  + 4}  \\  =   \sqrt{ \frac{25}{4} }  \\  =  \frac{5}{2}

6 0
3 years ago
HURRY PLEASE 6TH GRADE MATH HERE. A football field is 100 yards in length. How many inches long is a football field? 300 inches
Rufina [12.5K]

Answer:

3,600

Step-by-step explanation:

1 yard= 36 inches

36 inches*100= 3,600

__________________________________________________________

Brainliest? I am trying to get to a new rank so I can help more people and I would totally appreciate it if you did!

Merry Christmas!

3 0
3 years ago
Read 2 more answers
Paul answer 2 out of 5 questions correctly Jan answered 43% of her questions correctly and Juan answered 13 correctly and 6 inco
nika2105 [10]
2/5 = 40%
43%
13/19 = 68.4%

Juan
7 0
4 years ago
Sketch a graph of the polynomial function f(x) =x3− 2x2. Use it to complete the following:
AlladinOne [14]

Answer:

We have the function:

f(x) = x^3 - 2*x^2

To sketch this, we need to graph some points, and then just draw a line that passes through the points.

The graph of this equation is shown below.

Now we can complete the question.

If the graph is below the x-axis in some interval, the function is negative in that interval

If the graph is above the x-axis in some interval, the function is positive in that interval.

If the graph goes up in a interval, then the function is increasing in that interval

If the graph goes down on an interval, then the function is decreasing in that interval.

Then:

1) f is------ on the intervals (−∞, 0) and (0, 2).

Here we can see that the graph is below the x-axis in those intervals, then here we have:

f is negative on the intervals (−∞, 0) and (0, 2).

2) f is------ on the interval (2,∞)

Here the answer is positive:

f is positive on the interval  (2,∞)

3) fi is ------ on the interval (0, 4/3)

In the graph, you can see that the graph goes down in that interval, then the correct answer here is:

f is decreasing on the interval (0, 4/3)

4) f is------ on the intervals (−∞, 0) and (4/3, ∞).

In this case, we can see that the graph goes up in these intervals, then the correct answer here is:

f is increasing on the intervals (−∞, 0) and (4/3, ∞).

5 0
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