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Mrac [35]
2 years ago
15

Consider a sequence of transformations where ΔLMN is translated (x, y) → (x − 3, y + 4), reflected across the yaxis, and then re

flected across the x-axis. Predict the effect of the second transformation.
Mathematics
1 answer:
Svetlanka [38]2 years ago
5 0

the effect of the second transformation just is:

(x - 3, y + 4) → (-3 + 4, y + 4)

<h3>What will be the effect of the second transformation?</h3>

Here we have a sequence of transformations, we start with a point (x, y) which we:

  • First, we translate it 3 units to the left and 4 units up.
  • Second, we reflect it across the y-axis
  • Finally, we reflect it across the x-axis.

The second transformation is the first reflection, so we need to see what that reflection does.

First, the translation maps our point from (x, y) into (x - 3, y + 4).

Then, a reflection across the y-axis will only change the sign of the x-component of our point, so the effect of the second transformation just is:

(x - 3, y + 4) → (-3 + 4, y + 4)

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

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Write what the expressions below best represent within the context of the word problem.
Brilliant_brown [7]

X=2 NICKELS.

3*2=6 QUARTERS.

PROOF:

.25*6+.05*2=1.60

1.50+.10=1.60

1.60=1.60

3 0
4 years ago
Each student at some college has a mathematics requirement M (to take at least one mathematics course) and a science requirement
Furkat [3]

all students = 150

M = 60

S = 45

M and S = 25

(a) At least one of the two requirements:

M or S = M + S - (M and S) = 60 + 45 - 25 = 80

(b) Exactly one of the two requirements:

(M or S) - (M and S) = 80 - 25 = 55

(c) Neither requirement:

(all students) - (M or S) = 150 - 80 = 70

8 0
3 years ago
Formulate but do not solve the following exercise as a linear programming problem. Kane Manufacturing has a division that produc
earnstyle [38]

Answer:

z  - 2*x   -  1.5*y   =  0   maximize

subject to:

3*x  +  5*y   ≤  800

8*x  + 3*y   ≤   1200  

x, y  >  0

Step-by-step explanation:

Formulation:

Kane Manufacturing produce  x  units of model A (fireplace grates)

and  y units of model B

                  quantity   Iron cast lbs    labor (min)   Profit $    

Model  A          x               3                      8                  2

Model  B          y               5                      3                  1.50

We have   800 lbs of iron cast  and 1200 min  of labor available

We need to find out how many units  x  and units y per day to maximiza profit

First constraint   Iron cast lbs     800 lbs

3*x  +  5*y   ≤  800             3*x  +  5*y  +  s₁   =  800

Second constraint  labor    1200 min available

8*x  + 3*y   ≤   1200              8*x  + 3*y           + s₂  =  1200  

Objective function

z  =  2*x  +  1.5*y         to maximize    z  - 2*x   -  1.5*y   =  0  

x > 0   y  >  0

The first table is  ( to apply simplex method )

z         x        y       s₁      s₂       Cte

1        -2       -1.5     0      0          0

0        3         5       1       0        800

0        8         3       0       1       1200

7 0
4 years ago
Maxis taking a cross-country road trip. Gas prices vary as the friends travel across the US from $4 dollars per gallon on the ea
Alex787 [66]

Answer:

The quantity of fuel bought at $4 is 40.84 gallons

The quantity of fuel bought at $3 is 116.699 gallons

The quantity of fuel bought at $5 is 17.505 gallons

Step-by-step explanation:

Here we have

Gas used on East coast = X gallons

Gas consumed in the mid-US = Y gallons

Gas consumed in the West coast = Z gallons

Where Y = 2×(X + Z)..........(1)

4·X + 3·Y + 5·Z = 515.........(2)

X + Y  + Z = 150..................(3)

Therefore substituting for Y in equation (3) we have

X + 2×(X + Z)  + Z =  150

3·X + 3·Z = 150

X = (150 - 3·Z)/3 = 50 - Z

Therefore, equation (2) becomes;

4·(50 - Z) + 3·(2×((50 - Z) + Z)) + 5·Z = 515

200 - 4·Z + 300 -6·Z + 6·Z + 5·Z = 515

500 + 2·Z = 515

Z = 15

X = 50 - Z = 50 - 15 = 35

Y = 2×(X + Z) = 2×(35 + 15) = 2 × 50 = 100

(b) Whereby the bought 174 gallons based on the same ratio as in part (a), we have;

Ratio in part (a) is given as follows;

Proportion of Z gallons = 15/150 = 1/10

Proportion of X gallons = 35/150 = 7/30

Proportion of Y gallons = 100/150 = 2/3

Therefore the proportion of 174 gallons that was consumed in the East coast, X gallons = (7/30)×174 = 203/5 gallons  = 40.6 gallons

The proportion of 174 gallons that was consumed in the mid-US, Y gallons  = (2/3)×174 = 116 gallons  

The proportion of 174 gallons that was consumed in the West coast, Z gallons  = (1/10)×174 = 87/5 gallons = 17.4 gallons  

Based on price of per gallon, we have

The proportion of $515 that was consumed in the East coast on X gallons = $4 ×35 = $140

Proportion = 140/515= 28/103

The proportion of $515 that was consumed in the mid-US on Y gallons = $3 ×100= $300

Proportion = 300/515= 60/103

The proportion of $515 that was consumed in the West coast on Z gallons = $5 ×15= $75

Proportion = 75/515= 15/103

Therefore, the quantity of fuel bought at $4 = ((28/103) × 601)/4 = 40.84 gallons

The quantity of fuel bought at $3 = ((60/103) × 601)/3 = 116.699 gallons

The quantity of fuel bought at $5 = ((15/103) × 601)/5 = 17.505 gallons.

5 0
3 years ago
An inverse variation function has a k value of 8. Which ordered pair is on the graph of the function?
Vinvika [58]

The points on the graph of the inverse variation are of the form:

(x, 8/x)

<h3>Which ordered pairs are on the graph of the function?</h3>

An inverse variation function is written as:

y = k/x.

Here we know that k = 8.

y = 8/x

Then the points (x, y) on the graph of the function are of the form:

(x, 8/x).

So evaluating in different values of x, we can get different points on the graph:

  • if x = 1, the point is (1, 8)
  • if x = 2, the point is (2, 4)
  • if x = 3, the point is (3, 8/3)
  • if x = 4, the point is (4, 2)

And so on.

If you want to learn more about inverse variations:

brainly.com/question/6499629

#SPJ1

7 0
2 years ago
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