Use the tests for divisibility to determine which numbers divide evenly into the given number.

1 answer:

5 0

The numbers that can divide 648 evenly, using the divisibility tests, include 1, 2, 3, 4, 6, 8, 9, 12, and 18 and some multiples of any two numbers.

<h3>What is the divisibility test?</h3>

A divisibility test is performed to identify whether a number can be divided evenly by a fixed divisor without a remainder and without actually performing the division process.

Divisibility by 1: Every number is divisible by 1 = 648 (648/1).

Divisibility by 2: 648 is an even number and divisible by 2 = 324.

Divisibility by 3: Sum the digits (18). 18 is divisible by 3 = 6 (18/3).

Divisibility by 4: The last two digits (4 and 8) form a number (12) that is divisible by 4

Divisibility by 6: It is divisible by 2 and by 3

Divisibility by 8: If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.

Divisibility by 9: Sum the digits (18). 18 is divisible by 9

Divisibility by 12: 648 is divisible by 3 and by 4.

Divisibility by 18: 648 is divisible by 2 and by 9.

Learn more about the divisibility tests at brainly.com/question/24125354

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What is the sum of ? I will put a pic if the answer is correct ill mark brainlist

olga2289 [7]

$\text{The sum of } 1\frac{7}{10} \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}$

Solution:

Given that we have to find the sum of $1\frac{7}{10} \text{ and } 3\frac{3}{5}$

Let us first convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

Therefore,

$1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}$

Now we can add both the fractions

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18}{5}$

Make the denominators same

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}$