Find the slope:
(-19 - 11) / (-8 - 2) = (-30/-10) = 3
Find the y intercept:
y = mx + b
11 = 3(2) + b
b= 5
So equation is:
y = 3x + 5
The absolute value equation representing the length of the nail is :
A nail of length 1.05 inches is unacceptable
Actual Length of nail = 1 inch
Allowable variation = 1/32 inches
The minimum allowable length :
actual length - allowable variation
The maximum allowable length :
Actual length + allowable variation
The length of X, of the nail must be follow the equation :
Minimum ≤ X ≤ maximum
A nail of length 1.05 inches
Maximum nail length = 1 1/32 = 1.031
1.05 > 1.031 ; hence, it is greater than the maximum allowable length and hence, Unacceptabe
Learn more : brainly.com/question/24656203
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
x= 1, -1
Step-by-step explanation:
