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KengaRu [80]
3 years ago
6

Solve the system using elimination.

Mathematics
1 answer:
Leona [35]3 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:

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Find the equaton of the line passing through the points (2,11) and (-8, -19) y= ?x ?​
antoniya [11.8K]

Find the slope:

(-19 - 11) / (-8 - 2) = (-30/-10) = 3

Find the y intercept:

y = mx + b

11 = 3(2) + b

b= 5

So equation is:

y = 3x + 5

5 0
2 years ago
A company manufactures penny number 2 nails that are 1 inch in length. The actual length is allowed to vary by up to \displaysty
Diano4ka-milaya [45]

The absolute value equation representing the length of the nail is :

  • \frac{31}{32}  \leqslant x \leqslant 1 \frac{1}{32}

A nail of length 1.05 inches is unacceptable

Actual Length of nail = 1 inch

Allowable variation = 1/32 inches

The minimum allowable length :

actual length - allowable variation

  • 1 -  \frac{1}{32}  =  \frac{31}{32}

The maximum allowable length :

Actual length + allowable variation

  • 1 +  \frac{1}{32}  = 1 \frac{1}{32}

The length of X, of the nail must be follow the equation :

Minimum ≤ X ≤ maximum

\frac{31}{32}  \leqslant x \leqslant 1 \frac{1}{32}

A nail of length 1.05 inches

Maximum nail length = 1 1/32 = 1.031

1.05 > 1.031 ; hence, it is greater than the maximum allowable length and hence, Unacceptabe

Learn more : brainly.com/question/24656203

7 0
3 years ago
Anyone know the answer??
marissa [1.9K]
The answer should be C.

5 0
3 years ago
Read 2 more answers
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
2^x + 2^-x =5/2 pls I need d. ans​
yKpoI14uk [10]

Answer:

x= 1, -1

Step-by-step explanation:

6 0
3 years ago
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