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Anestetic [448]
2 years ago
10

Exercise: A lot consists of 20 defective and 80 non-defective items from which two items are chosen without replacement. Events

A & B are defined as A- (the first stens chosen is defective), B (the second item chosen is defective) a) What is the probability that both items are defective? b) What is the probability that the second item is defective?
​
Business
1 answer:
Inessa05 [86]2 years ago
5 0

The probability that both item is defective are  3.84%

The probability that the second is defective is  20%

<h3> What is the probability that both items are defective?</h3>

a) Remember that the question says they are drawn without replacement

hence

(20/100)*(19/99)

= 19/495

= 0.03838383

= 3.84%

b. What is the probability that the second item is defective?

(20/100)*(19/99) + (80/100)*(20/99)

= 0.03838383 + 0.1616

= 0.199999

= 0.2

= 20 percent

Read more on probability here: brainly.com/question/24756209

#SPJ1

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After years of research had been conducted at significant cost, Blanco Chemical Company determined a fertilizer they had been de
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as a "Deferred Development Cost" on the Balance Sheet.

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IAS 38.57 QUOTED

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Answer:

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