Answer:
To match each functions with the corresponding function formula when h(x) = 5 - 3x and g(x) = -3 x + 5.
1. k(x) = (3h - 5g)(x)
= = 3(5 - 3x)-5(-3 x + 5)
= = 15 - 9x + 15x - 25
K(x) = -10 + 6x
2. k(x) = (h - g)(x)
= = (5 - 3x) - (-3 x + 5)
= = 0
k(x) = 0
3. k(x) = (5g + 3h)(x)
= = 5(-3 x + 5)+3(5 - 3x)
= = -15x + 25 + 15 - 9x
k(x) = - 24x +40
4. k(x) = (3g + 5h)(x)
= = 3 (-3 x + 5) + 5(5 - 3x)
= = -9x + 15 +25 -15x
k(x) = -24x + 40
5. k(x) = (g + h)(x)
= = (-3 x + 5) + (5 - 3x)
k(x) = -6x + 10
6. k(x) = (5h - 3g)(x)
= = 5(5 - 3x) - 3(-3 x + 5)
= =25 - 15x + 9x - 15
k(x) = 10 - 6x
Answer:
y=2x+6
Step-by-step explanation:
y=mx+b
your two point that are [-1, 4] with 1 as x and 4 as y
replace y with 4 then replace m with 2 then put your negative one in () it should look like this
4=2(-1)+b then do what in Parentheses
that will give you -2 then add 2 to 4 and that will give u 6
y=2x+6
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Answer:
- parallel: y = 4x -6
- perpendicular: y = -1/4x +27/4
Step-by-step explanation:
If we want the new line to be written in slope-intercept form, we need to find the new value of the y-intercept. The equation of the line is ...
y = mx +b . . . . . . . for slope m and y-intercept b
Solving for b gives ...
b = y -mx . . . . . . . subtract mx from both sides.
The values of x and y come from the point we want the line to pass through. The value of m will be the same for the parallel line as for the given line: 4. For the perpendicular line, it will be the opposite reciprocal of this: -1/4.
<u>Parallel line</u>
b = 6 -4(3) = 6 -12 = -6
y = 4x -6
Perpendicular line
b = 6 -(-1/4)(3) = 6 +3/4 = 27/4
y = -1/4x +27/4
f(x) = (x - 4)^2 - 5
Vertex (4 , -5)
This function opens upward and has min. value = -5
So range y >= - 5
So answer is A. -5 <= f(x) < ∞