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maks197457 [2]
3 years ago
5

Which of the following statements is true about the three quadrilaterals?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0
A and C should be the answer, hope this helps
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Graph triangle cuz with vertices x(-2, -4), y(2, -1), and z(4, -3) on the coordinate grid.
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This is what I got pls mark me brainlest

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A touchdown it's worth six points. Additionally you score an extra point if you can take a field goal. Is the total number of po
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No because it would be 7/6 which is not proportional.
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4 years ago
A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles: An oval is formed by a rectangle
sesenic [268]
We can solve this by first finding the diameter of the two semicircles. We know that the width of the rectangle is 27 inches, which also happens to be the diameter of the circle.

The circumference of a circle is 2πr or πd. The problem says that it is a semicircle, however, it says that there are two of them. Since the two semicircles are the same size, we know that they can combine to form one circle, so we can just find the circumference of one circle to account for both of the semicircles:

C=27π inches

We also know that the length of the rectangle is 60 inches. We only want to find the perimeter of the frame, so we don't have to account for the widths of the rectangle because it is inside the frame. Therefore, the two sides of the rectangle together are 120 inches. Now we can add this to the circumference we found:

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5 0
3 years ago
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What is the area of the shaded region?
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Answer:

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A company producing tennis racquets found that 3% of the racquets they produce are defective. The racquets are sent to shops in
a_sh-v [17]

Answer:

0.82

Step-by-step explanation:

The question says that three percent (3 out of 100) of the rackets (racquets) produced by the company are found to be defective.

First thing to calculate is the probability that 1 in a box of 6 rackets are defective.

That probability is gotten by cross multiplying, as illustrated below;

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x - 6

x = (6×3)/100 = 18/100 = 0.18

Since the probability of having/finding 1 defective racket in a box of 6 is 0.18, the probability of finding more than 1 (minimum of 2 and maximum of all six) defective rackets in same box would be (1 - 0.18) = 0.82

6 0
3 years ago
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