The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
For two lines to be perpendicular, the slope of one line is the negative reciprocal of the other line. The equation of the given line is
y = 2x - 2
Comparing with the slope intercept form,
Slope, m = 2
This means that the slope of the line that is perpendicular to it is -1/2
The given points are (-3, 5)
To determine c,
We will substitute m = -1/2, y = 5 and x = - 3 into the equation, y = mx + c
It becomes
5 = -1/2 × - 3 + c
5 = - 3/2 + c
c = 5 + 3/2
c = 13/2
The equation becomes
y = -x/2 + 13/2
No,because your supposed to multiply it by the same number.
Answer:
38-15c-4
Step-by-step explanation:
38-x=12c+4+3c
38-x=15c+4
x=38-15c-4
Y = (2)^(n+1) - 2
is the general term for this.
