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2 years ago

What is the range of the given function?

Mathematics

1 answer:

shepuryov [24]2 years ago

6 0

It is found that the range of the given function will be y ≤ 9. Then option B is correct.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The given function is f(x)

f(x) = {x + 7, if x>2

{-2x + 13 if x ≤ 2

Therefore, when x is less than 2, we have the output as

x + 7 = 9

When x is equal to or greater than 2, we have the output as

-2x + 13 = -2(2) + 13 = 9

Hence, we can conclude that the range of the given function will be y ≤ 9.

Then option B is correct.

Learn more about the domain and range of the function:

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On a certain hot summer's day, 691 people used the public swimming pool. The daily prices are $1.50 for children and $2.25 for

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Answer:

Step-by-step explanation:

On a certain hot summer's day, 691 people used the public swimming pool. The daily prices are $1.50 for children and $2.25 for adults. The receipts for admission totaled $1260.75. How many children and how many adults swam at the public pool that day?

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3 years ago

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
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The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
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$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

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3 years ago

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It is said that two variables A and B are related when the distribution of the values of one of the two variables differs according to the values of the other.

That is, when variable A grows then variable B also grows. This is known as positive correlation

When variable A grows then variable B decreases. This is known as negative correlation.

In the scatter plot you may notice that when variable A increases then variable B also increases, in an approximately linear relationship. Therefore it can be said that there is a positive and linear association.

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