Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
Please give me Brainliest
B then C
i have a 20 character limit so i’m just typin here
Answer:
1
Step-by-step explanation:
Simplify the following:
7 - 1/2×12
(-1)/2×12 = (-12)/2:
7 + (-12)/2
12/2 = (2×6)/2 = 6:
7 - 6
21/3 = (3×7)/3 = 7:
7 - 6
7 - 6 = 1:
Answer: 1
Answer:
Ken;
Step-by-step explanation:
Ken grew 4/5 of an inch. 4/5=0.8
Sang grew 3/8 of an inch. 3/8= 0.375
0.8 > 0.375 so Ken grew more.
0.8 - 0.375 = 0.425
So, Ken grew 0.425 more inches than Sang grew. 0.425 is also the same thing as 17/40.
